Answer:
$3,659.82
Step-by-step explanation:
Adding to the checkbook those debits and credits not already there brings its balance to ...
... $3045.58 +651.84 -37.60 = $3659.82
Adjusting the bank's balance by the deposits and checks not already there brings its balance to ...
... $4262.92 +220.05 -325.50 -497.65 = $3659.82
Thus, the reconciled accounts will agree on the balance $3659.82.
(2x) + 11 < 44
x is multiplied by two because we are looking for twice of x. 11 is added to the 2x because we are looking for eleven more than the sum of twice of x. Since 2x + 11 is less than 44, we use the lesser than ( < ) symbol.
Step-by-step explanation:
= 4x-x+5x+1+8-2
=8x+7
proved##
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
1. C
2. B,C,E
Hope that helps.