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4 years ago

The sum of three consecutive numbers is 243. What is the third number?

1 answer:

3 0

Three consecutive numbers can be written as x, x+1, and x+2, but they also can be written x, x-1, and x-2 where x is the biggest number.

sum means adding... so

$x + x - 1 + x - 2 = 243$
combine like terms and solve for x!

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1/2 x + 3/4=1 please help me!

Kipish [7]

X=1/2 :)))))))))))))

8 0

3 years ago

sarah the cheetah ran 100 meters at a speed of 16.8 meters per second. an olympian ran the 100 meter dash in 9.6 seconds . how m

Alexus [3.1K]

Answer:

3.6477seconds

Step-by-step explanation:

Sarah the cheetah ran the 100 meters in 5.9523s. Subtract 5.9523 from 9.6

7 0

3 years ago

Evaluate: 5/8 - (1/4)²

Viefleur [7K]

Answer:

5/8 - (1/4)^2 = 0.5625, hope this helps!

6 0

4 years ago

You have used the Distributive Property totransform numerical expressions such as (5)(3) +(2)(3) to (5 + 2)(3). How would you tr

barxatty [35]

We have the expression

$5x+2x$

We have to convert the expression in a single-term expression. We apply the distributive property:

$5x+2x=(5+2)\cdot x=7x$

b) We have to substitute five different values into the expressions 5x+2x and 7x-1.

The first expression is equal to 5x+2x=7x.

We then can predict that the difference between 7x and 7x-1 is 1.

For example, for x=2, we have 7x=7*2=14 and 7x-1=7*2-1=14-1=13.

We can calculate if the two expressions can be equal, we write:

$\begin{gathered} 5x+2x=7x=7x-1 \\ 7x=7x-1 \\ 7x-7x=-1 \\ 0=-1\longrightarrow\text{False} \end{gathered}$

There is no value that can make both expressions equal.

Both equations have a difference of 1 for any value of x.

8 0

2 years ago

A figure is broken into a rectangle and a triangle. The triangle has a base of 2 and two-thirds feet and height of 3 feet. The r

ohaa [14]

Answer:

$b=2\frac23\:\sf ft$

Area of triangle = 4 ft²

Area of rectangle = $6\frac23\: \sf ft^2$

Area of irregular figure = $10\frac23\: \sf ft^2$

Step-by-step explanation:

$\begin{aligned}\sf Base\:of\:triangle\:(b) & = 5-2\frac13\\\\& = \dfrac{15}{3}-\dfrac73\\\\ & = \dfrac83\\\\ & = 2\frac23\:\sf ft \end{aligned}$

$\begin{aligned}\sf Area\:of\:a\:triangle & =\dfrac12 \sf \times base \times height\\\\& = \dfrac12 \times b \times 3\\\\ & = \dfrac12 \times \dfrac83 \times \dfrac31\\\\ & = \dfrac{24}{6}\\\\ & = 4\: \sf ft^2\end{aligned}$

$\begin{aligned}\sf Area\:of\:rectangle& =\sf length \times width\\\\& = 5 \times 1\frac13\\\\ & = \dfrac51\times \dfrac43\\\\& = \dfrac{20}{3}\\\\ & = 6\frac23\: \sf ft^2\end{aligned}$

$\begin{aligned} \sf Area\:of\:irregular\:figure & = \sf area\:of\:triangle+area\:of\:rectangle\\\\ & = 4 + 6\frac23\\\\ & = 10\frac23\: \sf ft^2\end{aligned}$

5 0

2 years ago

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