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AleksandrR [38]
4 years ago
8

The sum of three consecutive numbers is 243. What is the third number?

Mathematics
1 answer:
marishachu [46]4 years ago
3 0
Three consecutive numbers can be written as x, x+1, and x+2, but they also can be written x, x-1, and x-2 where x is the biggest number.

sum means adding... so

x + x - 1 + x - 2 = 243
combine like terms and solve for x!
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Gene add 35 + 9 how can she solve using only equations to model her thinking explain​
Ulleksa [173]

She can add 35 and 9 which equals 44

4 0
4 years ago
My son wants to make and equilateral triangle eith sticks and strings. Explain how he could do this?​
Ivanshal [37]

Answer:

Step-by-step explanation:

1. Cut six desired measures of string to properly wrap and tied around each end of the three sticks

2. Once fastened, bring two of the sticks together making one the bottom (base) and the other a side (angle).

3.Cut a tiny piece of rope to interlock with the rope you already have tied on the ends.

4.Tie the ends together with the new cut of string and make your desired angle as you tighten it.

5. Mirror Step 4 for the other end of the bottom stick (base), while most importantly mirroring the desired angle of step 4.

This should give you a proper equilateral triangle made out of sticks and string or anything of these two materials.

8 0
2 years ago
PLEASE HELP ME <br> There is supposed to be two answers
Nuetrik [128]
A and D:)
Hope I helped!
6 0
3 years ago
Here's this too!!!!!
Oksanka [162]

Answer:

6. (a-4)(a+9)

7. (3p+4)(p-2)

8. Will explain below.

9. (5b+4)(5b-4)

Step-by-step explanation:

HELLOOO IM BACK

6. -4*9 = -36 (the variable), 9-4 = 5 (a) , so a^2 +5a - 36 is fulfilled.

7. 4*-2 = -8, 4-2 = 2, so 3p^2 - 2p - 8 is fulfilled.

9. 25b^2 = (5b)^2

16 = 4^2

Using the difference of squares formula, a^2-b^2= (a+b)(a-b)

3 0
4 years ago
Suppose you have a group of 8 male and 4 female volunteers. how many ways are there to choose 6 of these volunteers for a treatm
Kay [80]
Since volunteers can be of any sexe (no precision given in your problem), then we can consider the question as  how many group of 6 we can make with 12 persons:
It's a combination of 6 chosen among 12

¹²C₆ = (12!)/(6!).(12-6!)

²C₆ = (12!)/(6!).(6!)<span>

</span>¹²C<span>₆</span> = 924 Ways

6 0
4 years ago
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