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Answer:
Encrypted message: CPONYIERTN
Explanation:
Message = ENCRYPTION
keyword = ONE
keyword ONE is of length 3 so the rows are of length 3
Permutation is given by the alphabetical order of the letters in the keyword ONE. Here E appears first in alphabet, then comes N and in last comes O so the order would be 321.
Now the message ENCRYPTION is written in tabular form with width of the rows defined by a keyword ONE
O N E
3 2 1
E N C
R Y P
T I O
N
Now this message is read by the column in alphabetic order of the keyword ONE.
Since alphabetic order of E is 1 so the column under E is read first which has the letters:
CPO
Then column under N is read which has the letters:
NYI
In the last the column under O is read which has the letters:
ERTN
So the encrypted message is:
CPONYIERTN
Answer:
a. 6 bits
b. 1
Explanation:
Ans (a)
40 Characters need to be represent by binary coded Zebronian (BCZ) , So You will need 6 bits.
5 bits wold only give you 32 = 2 x 2 x 2 x 2 x 2 unique characters.
So 6 bits would allow you to represent 64 characters.
Ans(b)
BCD = Binrary Coded Decimal is very common in electronics, particularly it displays numerical data.
BCD Encodes each digit of a decimal number into 4 digit binary form.
Each decimal digit is indiviidually converted to oits binary equivalent
For Example : 146 , the decimal degits are replaced by 0001 , 0100 and 0110 respectively
Addition
1 0 = 10 is binary value of 2 2
+1 1 = 11 is binary value of 3 + 3
---------- -----------
1 0 1 5 Ans
Subtraction
1 1= binary value of 3 3
- 1 0 = binary value of 2 - 2
--------- -----------
0 1 1 Ans
In my answer I am making an assumption that there is no runtime error, if there is then the error is “a run-time error”.
The answer is the program suffers from a Logic Error
