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vladimir2022 [97]
3 years ago
14

An identifying value called a/an ____ is assigned by the java runtime to an object when it is created, to allow the java runtime

to tell objects apart
Computers and Technology
1 answer:
uranmaximum [27]3 years ago
8 0
This is going to be called a hash code. =)
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Which case would benefit from Explainable Artificial Intelligence (AI) principles?
Nadya [2.5K]

The case that will benefit from Explainable Artificial Intelligence (AI) principles is a doctor who depends on AI to make diagnosis.

Using Explainable Artificial Intelligence principles of supported evidence, understandable and accurate explanations, and knowledge limit as designed for AI, will save the doctor and all medical staff enormous amount of time.

Explainable Artificial Intelligence enables all medical staff to focus on correct medical interpretation and treatment instead of wasting time on repetitive medical tasks.

In comparison, the medical doctor will benefit more than a music streaming platform recommending a song, a navigation platform suggesting fastest routes, or a social media platform that identifies faces from a picture.

Thus, a medical doctor will find Explainable Artificial Intelligence principles useful to reduce some of the repetitive tasks that she undertakes, thereby focusing her attention on providing appropriate medical care to the patients.

Learn more about Explainable Artificial Intelligence here: brainly.com/question/22650312

5 0
3 years ago
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Which of the following is the correct style tag for having the web page's text be aligned to the right?
uysha [10]

Answer:

B. style=text-align: right

Explanation:

text-align is a CSS property having 5 types of values. Each of values define below.

left - Aligns content to left.

right - Aligns content to right.

center - Centers the content.

justify - Depends on the width of the content, it will align itself to both left and righ

inherit - It specifies the the value of text-align should be taken from parent element.

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A computer that passes the Turing test might show that
kow [346]
A computer that passes the Turing test might show that has the ability to exhibit intelligence similar to, or indistinguishable from that of a human.
8 0
3 years ago
Use a for/else loop to traverse through the key names in the dictionary below in order to find Mr. Potatohead’s mailing address.
Tatiana [17]

Dictary = {

'code':6734,

'dept': 'sales',

123-45-6789:"Mr.Potato Head \n234 Potato Lane \nPotato Chip, ID 77725"

}

for i in Dictary.keys():

   if i == 123-45-6789:

       print(Dictary.get(i))

       break

else:

   print("Key not found")

You can further test this code by deleting Mr.Potato head's info from the dictionary. I hope this helps!

4 0
3 years ago
Write an application that uses String method region-Matches to compare two stringsinput by the user. The application should inpu
SOVA2 [1]

Answer:

Explanation:

The following program creates a function called region_Matches that takes in two strings as arguments as well as an int for starting point and an int for amount of characters to compare. Then it compares those characters in each of the words. If they match (ignoring case) then the function outputs True, else it ouputs False. The test cases compare the words "moving" and "loving", the first test case compares the words starting at point 0 which outputs false because m and l are different. Test case 2 ouputs True since it starts at point 1 which is o and o.

class Brainly {

   public static void main(String[] args) {

       String word1 = "moving";

       String word2 = "loving";

       boolean result = region_Matches(word1, word2, 0, 4);

       boolean result2 = region_Matches(word1, word2, 1, 4);

       System.out.println(result);

       System.out.println(result2);

   }

   public static boolean region_Matches(String word1, String word2, int start, int numberOfChars) {

       boolean same = true;

       for (int x = 0; x < numberOfChars; x++) {

           if (Character.toLowerCase(word1.charAt(start + x)) == Character.toLowerCase(word2.charAt(start + x))) {

               continue;

           } else {

               same = false;

               break;

           }

       }

       return same;

   }

}

3 0
3 years ago
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