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choli [55]
3 years ago
11

the sum of three numbers is 45. the second of the three numbers is three more than twice the first number, x. the third number i

s two more than the first number, x. which equation can be used to solve for the first number, x?

Mathematics
2 answers:
Feliz [49]3 years ago
6 0

Answer:

x+ (2x+3) +(x+2)=45

Step-by-step explanation:

First number is x

So using this ,second number which is three more than twice of the first can be written as 2x+3

Now , The third number is two more than the first so it is x+2

Sum of the three numbers can be written as

x+ (2x+3) +(x+2)

In the question it is given that the sum is 45 so we can equate the equation in x to the given sum to solve it for x .

Hence

x+ (2x+3) +(x+2) =45

dolphi86 [110]3 years ago
5 0
The numbers are 20,15 and 10
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