Answer:
1 year , 9 months or 21 months
Step-by-step explanation:
that is the solution above
Answer:

Step-by-step explanation:
It is a result that a matrix
is orthogonally diagonalizable if and only if
is a symmetric matrix. According with the data you provided the matrix should be

We know that its eigenvalues are
, where
has multiplicity two.
So if we calculate the corresponding eigenspaces for each eigenvalue we have
,
.
With this in mind we can form the matrices
that diagonalizes the matrix
so.

and

Observe that the rows of
are the eigenvectors corresponding to the eigen values.
Now you only need to normalize each row of
dividing by its norm, as a row vector.
The matrix you have to obtain is the matrix shown below
Answer:
Quad One: A
Quad Two: C
Quad Three: B
Quad Four: E
Hope This Helps! Have A Nice Night!!
For this case we have the following system of equations:

From the first equation we clear "x":

We substitute in the second equation:

We apply distributive property:

We add similar terms:

We add 65 to both sides:

We divide between 22 on both sides:

We look for the value of the variable "x":

Thus, the solution of the system is:

ANswer:
