the sum of three numbers is 45. the second of the three numbers is three more than twice the first number, x. the third number i
s two more than the first number, x. which equation can be used to solve for the first number, x?
2 answers:
Answer:
x+ (2x+3) +(x+2)=45
Step-by-step explanation:
First number is x
So using this ,second number which is three more than twice of the first can be written as 2x+3
Now , The third number is two more than the first so it is x+2
Sum of the three numbers can be written as
x+ (2x+3) +(x+2)
In the question it is given that the sum is 45 so we can equate the equation in x to the given sum to solve it for x .
Hence
x+ (2x+3) +(x+2) =45
The numbers are 20,15 and 10
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