If the function f (2) 3x2 + bx + 2 has no real roots, which of the following could be the value of b? -7, -1, 8, 0
1 answer:
Answer:
b could be -1 or 0
Step-by-step explanation:
f(x) = 3x^2 +bx+2
if it has no real roots, the discriminant must be less than zero
b^2 -4ac <0
a=3 b=b c=2
b^2 - 4(3)(2) <0
b^2 - 24 <0
b^2 < 24
Taking the square root of each side
b< 2 sqrt(6) and b > 2 sqrt(6)
b could be -1 or 0
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The answer should be:
20.875
Hope this helps.
Answer:
Therefore four rational numbers between 1 and 2 are 9/8, 5/4, 3/2, and 7/4 Step-by-step explanation:
I got 42.5 cuz 4x+10=180 then take away 10 from both sides so 4x=170 and you divide each side by 4
<u>Define x:</u>
Let the first number be x.
1st number = x
2nd number = x + 1
3rd number = x + 2
<u>Construct equation:</u>
x + x + 1 + x + 2 = 4(x + 1)
3x + 3 = 4(x + 1)
Answer: 3x + 3 = 4(x + 1)
Answer:
1
Step-by-step explanation:
16 * 1/2 = 8
8 - 7 = 1
