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2 years ago

If the function f (2) 3x2 + bx + 2 has no real roots, which of the following could be the value of b? -7, -1, 8, 0

Mathematics

1 answer:

lina2011 [118]2 years ago

3 0

Answer:

b could be -1 or 0

Step-by-step explanation:

f(x) = 3x^2 +bx+2

if it has no real roots, the discriminant must be less than zero

b^2 -4ac <0

a=3 b=b c=2

b^2 - 4(3)(2) <0

b^2 - 24 <0

b^2 < 24

Taking the square root of each side

b< 2 sqrt(6) and b > 2 sqrt(6)

b could be -1 or 0

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Pls can someone help me and have it right

dangina [55]

Answer:

Problem 1:

a. x=2

b. x=3

c. x=1

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Step-by-step explanation:

Given in problem 1:

(a). The equation is $\frac{x}{6} > 1$

It holds true for all values of $x> 6$ .

Let us say $x=12$ ,

$\frac{x}{6}=\frac{12}{6} =2$ which is greater than 1.

(b). The equation is $\frac{x}{6} < 1$

It holds true for all values of $x< 6$ .

Let us say $x=3$

$\frac{x}{6} =\frac{3}{6} =\frac{1}{2}$ which is less than 1.

(c). The equation is $\frac{x}{6} = 1$

It holds true for only $x= 6$ .

Let us say $x=6$ ,

$\frac{x}{6} =\frac{6}{6}=1$ which is equal to 1.

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Therefore these are the values which hold true to the equation in problem 1 and 2.

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Step-by-step explanation:

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