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3 years ago

If the function f (2) 3x2 + bx + 2 has no real roots, which of the following could be the value of b? -7, -1, 8, 0

Mathematics

1 answer:

lina2011 [118]3 years ago

3 0

Answer:

b could be -1 or 0

Step-by-step explanation:

f(x) = 3x^2 +bx+2

if it has no real roots, the discriminant must be less than zero

b^2 -4ac <0

a=3 b=b c=2

b^2 - 4(3)(2) <0

b^2 - 24 <0

b^2 < 24

Taking the square root of each side

b< 2 sqrt(6) and b > 2 sqrt(6)

b could be -1 or 0

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The regular price of a stainless steel iron is $30.00. Today it is on sale for 40% off. What is the sale price?

vagabundo [1.1K]

The answer is $18.00 dollars. Have a nice day!

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3 years ago

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The length of a rectangle is 4 centimeters more than twice its width of the perimeter of the rectangle is 86centimeters find the

lana66690 [7]

Answer:

$Width= 13 cm$

$length=30cm$

Step-by-step explanation:

Let the length of the rectangle be 'L'

And the width of the rectangle be 'W'

$Perimeter= 86 cm$

According to the statement:

$Length= 2*Width+4\\L=2W+4$

Perimeter of a rectangle= 2(Length+Width)

$86=2(2W+4+W)\\86/2=3W+4\\43=3W+4\\3W=43-4\\3W=39\\W=39/3\\W=13 cm\\\\Length(L)=2W+4\\=2(13)+4=26+4=30 cm\\Length=30 cm$

$Width= 13 cm$

$length=30cm$

6 0

3 years ago

Solve the equations and graph the solution

jenyasd209 [6]

Given:

The inequalities are:

$-5x$ or $2x$

To find:

The solution for the given inequalities and graph the solution.

Solution:

We have,

$-5x$ or $2x$

Solve the above inequalities separately.

$-5x$

Divide both sides by -5.

$x>\dfrac{-3}{-5}$

$x>\dfrac{3}{5}$ ...(i)

And,

$2x$

Divide both sides by 2.

$x$

$x$ ...(ii)

From (i) and (ii). we get

$x$ or $x>\dfrac{3}{5}$

The interval notation of the solution is $(-\infty,-4)\cup \left(\dfrac{3}{5},\infty\right)$ .

The graph of the solution is shown below.

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3 years ago

Solve -103 = 6x + 17. (A) -16 (B) 16 (C) -20 (D) 20

andrew11 [14]

The correct answer is C (-20) let me know if you want to know how I got that answer

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3 years ago

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What is the slope y+2=1/4(x-3)

ioda

Answer:

$m=\frac{1}{4}$

Step-by-step explanation:

Given

$y+2=\frac{1}{4}(x-3)$

Required

Find the slope

$y+2=\frac{1}{4}(x-3)$

Subtract 2 from both sides

$y+2-2=\frac{1}{4}(x-3) - 2$

$y=\frac{1}{4}(x-3) - 2$

Open bracket

$y=\frac{1}{4}x-\frac{1}{4}*3 - 2$

$y=\frac{1}{4}x-\frac{3}{4} - 2$

Take LCM

$y=\frac{1}{4}x+\frac{-3 - 8}{4}$

$y=\frac{1}{4}x+\frac{-11}{4}$

$y=\frac{1}{4}x-\frac{11}{4}$

An equation has the form:

$y = mx + b$

Where

$m = slope$

By comparing: $y = mx + b$ and $y=\frac{1}{4}x-\frac{11}{4}$

$m=\frac{1}{4}$

So, the slope is 1/4

6 0

3 years ago