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zlopas [31]
3 years ago
5

Find the product. Write the answer in simplest form. 2 2/7 x 5/8 x 4 1/10??

Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

5 6/7

Step-by-step explanation:

107×4110=?

10

7

×

41

10

=

?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

10×417×10=41070

10

×

41

7

×

10

=

410

70

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 410 and 70 using

GCF(410,70) = 10

410÷1070÷10=417

410

÷

10

70

÷

10

=

41

7

The fraction

417

41

7

is the same as

41÷7

41

÷

7

Convert to a mixed number using

long division for 41 ÷ 7 = 5R6, so

417=567

41

7

=

5

6

7

Therefore:

107×4110=567

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Scientific notation of 1,304,000,000
svet-max [94.6K]
1.304 x 10⁰ = 1.304 x 1 = 1.304

1.304 x 10¹ = 1.304 x 10 = 13.04

1.304 x 10² = 1.304 x 100 = 130.4

1.304 x 10³ = 1.304 x 1,000 = 1,304

1.304 x 10⁴ = 1.304 x 10,000 = 13,040

1.304 x 10⁵ = 1.304 x 100,000 = 130,400

1.304 x 10⁶ = 1.304 x 1,000,000 = 1,304,000

1.304 x 10⁷ = 1.304 x 10,000,000 = 13,040,000

1.304 x 10⁸ = 1.304 x 100,000,000 = 130,400,000

* 1.304 x 10⁹ = 1.304 x 1,000,000,000 = 1,304,000,000 *

----------------

ANSWER:

1.304 x 10⁹ = 1.304 x 1 Billion
8 0
3 years ago
El tamaño de cierto cultivo de bacterias se multiplica por 2 cada 30 minutos. Si suponemos que el cultivo tiene inicialmente 256
Oduvanchick [21]

Answer:

La población de bacterias después de tres horas es de 2^{14} bacterias.

Step-by-step explanation:

En este enunciado observamos un caso de progresión geométrica, en donde la población de bacterias se duplica cada treinta minutos, es decir:

\frac{p(n\cdot\Delta t)}{p(0)} = 2^{n} (1)

Donde:

\Delta t - Intervalo de tiempo requerido para el incremento geométrico de la población, en minutos.

n - Número de períodos para incremento geométrico, sin unidad.

Sabemos que la población inicial de bacterias es 256 y que 3 horas son 6 veces 30 minutos. Entonces, tenemos la siguiente razón:

\frac{p(6\cdot \Delta t)}{p(0)} = 2^{6} (2)

Si sabemos que p(0) = 256, entonces p(6\cdot \Delta t) es:

p(6\cdot \Delta t) = 2^{6}\cdot p(0)

p(6\cdot \Delta t) = 2^{6}\cdot (256)

p(6\cdot \Delta t) = 2^{6}\cdot 2^{8}

p(6\cdot \Delta t) = 2^{14}

La población de bacterias después de tres horas es de 2^{14} bacterias.

4 0
3 years ago
What’s the answer to this
Greeley [361]

Answer:

x-intersepts- (-11/8, 0)

y-intersepts- (0, 11/5)

8 0
3 years ago
4. What is the density of an object<br> with a mass of 20g and a volume of<br> 4ml?
kow [346]

Answer:

5000 kilogram/cubic meter

Step-by-step explanation:

7 0
3 years ago
359
Minchanka [31]

i think the answer is 35° because the triangles are congruent to each other

5 0
3 years ago
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