All categories

3 years ago

Which equation has no solution?

Mathematics

1 answer:

Airida [17]3 years ago

7 0

Answer: B: 3x + 4 = 3(x - 5) (has no solution)

Step-by-step explanation: (these have solutions)

C: X+ 6 = 6x = 6/5

A: x + 3 = 5(x+3) = −3

D: 5x + 2 = 4x - 3 = −5

You might be interested in

Help me with this geometry question please I need it quick

stealth61 [152]

I got 25 (24.738634) sry if wrong

8 0

3 years ago

If 1 card is drawn at random from a standard 52-card deck, what is the probability that the card drawn is a king?

Ahat [919]

Answer:

1/13 chance or roughly 7.7% chance.

Step-by-step explanation:

There are 4 Kings in a standard 52-card deck. If one King was to be pulled out, you'd get a probability of 4/52 chance of pulling a king. Simplified, 4/52 is 1/13 chance.

5 0

3 years ago

Write the following expression with as few symbols as possible, using the notational conventions:

My name is Ann [436]

Answer:

The simplified expressions are (x + y·z' + t) and x·(x + y' + z) respectively.

Step-by-step explanation:

The expressions provided are:

$(i)\ x+((y\times (z')) +t)\\\\(ii)\ x\times((x+(y'))+z)$

(i)

Simplify the first expression with as few symbols as possible:

$x+((y\times (z')) +t)=x+(yz'+t)$

$=x+yz'+t$

(ii)

Simplify the second expression with as few symbols as possible:

$x\times((x+(y'))+z)=x\times ((x+y')+z)$

$=x (x+y'+z)$

Thus, the simplified expressions are (x + y·z' + t) and x·(x + y' + z) respectively.

6 0

3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

3 years ago

51: Y = 3: 5 value of Y

ivann1987 [24]

Answer:Y=25:3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers