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sveticcg [70]
3 years ago
8

Can someone help me wit da question listed in da picture?

Mathematics
2 answers:
satela [25.4K]3 years ago
7 0

Answer:

it would be 14x

Step-by-step explanation:

ycow [4]3 years ago
5 0

Answer:

Option C)

Step-by-step explanation:

When Solving these equations rember PEMDAS

  • Parentheses
  • Exponits
  • Multiply
  • Divide
  • Add
  • Subtract

Hope this helps, PEMDAS is just an easy way to show what to do first, second, Ect.

Please Rate Brainiest!

-Aslina

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Please help thank you
True [87]
Hello again
Answer: 1 1\3
~hope i help~
7 0
3 years ago
Read 2 more answers
From the sum of 4a + b + c and 9a - c subtract the sum of 18a - b - c and 14a - 2b - c
sergiy2304 [10]

1:-

\\ \rm\Rrightarrow 4a+b+c+9a-c

\\ \rm\Rrightarrow 4a+9a+b+c-c

\\ \rm\Rrightarrow 13a+b

2:-

\\ \rm\Rrightarrow 18a-b-c-(14a-2b-c)

\\ \rm\Rrightarrow 18a-b-c-14a+2b+c

\\ \rm\Rrightarrow 18a-14a-b+2b-c+c

\\ \rm\Rrightarrow 4a+b

5 0
3 years ago
Read 2 more answers
A single-server waiting line system has an arrival pattern characterized by a Poisson distribution with 3 customers per hour. Th
sweet-ann [11.9K]

Answer:

18 minutes

Step-by-step explanation:

Given that:

The arrival time = 3 customers / hour

The avg. service rate (s) = 12 minutes per customer

To hour, we have:

s = \dfrac{60}{12}

s = 5 customers/ hour

Thus, the required average time for a customer needs to wait in line is:

= \dfrac{3}{5}\times (5-3) hours \\ \\ = \dfrac{3}{5}\times 2 \\ \\ = \dfrac{3}{10} \ hours

To minutes;

= 3 \times \dfrac{60}{10} \ minutes

= 18 minutes

3 0
3 years ago
I need the answer fast
Fantom [35]

Answer:

B. What was the highest temperature this month?

Step-by-step explanation:

Rory is recording the <em>high</em><em>est</em><em> temperature</em> for the duration of the day for month's worth of data.

B. is the easiest one to answer, as you simply will have to look for the greatest number within the set, and that will be the answer.

A. is too broad, and does not imply that only the "high temperature" is needed, rather just a leveled temperature within day in that month.

C. is the opposite of what Rory had recorded, and without data, he cannot answer it.

D. is answerable as well, but, again, the only temperature recorded is the high temperature. Temperature can fluctuate depending on the time of the day, and can be in the 50s one hour and the 90s in another.

~

5 0
3 years ago
PLEASE HELP
postnew [5]

Answer:

Below

Step-by-step explanation:

Substituting the given values:

f(6) = 6(2/3) - 2 =   cube root of 6^2 - 2 = cube root 36 - 2

f(-6)=  (-6)(2/3) - 2 =   cube root of(-6)^2 - 2 = cube root 36 - 2

So This is true,

f(6) =   cube root of 6^2 - 2 = cube root 36 - 2 = 1.3019

2 * f(3) = 2 *  (cube root of 3^2 - 2 )  =  2 * (cube root of 9 - 2) = 0.1602

So False,

4 0
3 years ago
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