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sveticcg [70]
3 years ago
8

Can someone help me wit da question listed in da picture?

Mathematics
2 answers:
satela [25.4K]3 years ago
7 0

Answer:

it would be 14x

Step-by-step explanation:

ycow [4]3 years ago
5 0

Answer:

Option C)

Step-by-step explanation:

When Solving these equations rember PEMDAS

  • Parentheses
  • Exponits
  • Multiply
  • Divide
  • Add
  • Subtract

Hope this helps, PEMDAS is just an easy way to show what to do first, second, Ect.

Please Rate Brainiest!

-Aslina

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They will have to pay 24$ each for the both of them for all 4 days

8 0
3 years ago
Read 2 more answers
North Carolina: 79.6 years
Aliun [14]

Answer:

See below

Step-by-step explanation:

Think: They want us to make a box-o-gram (histogram and box-whisker-plot combo).

Identify: They gave us the information we need and we know that health care varies in each state, so that affects the life longevity and also different imcomes affect the care people resceive. We will make the box-o-gram after ordering the data appropriately.

Do: After ordering the numbers from least to greatest, we make calculations for the medians and mean. Here are the answers:

Least: 75 (Need to round up for this)

Greatest: 83 (Need to round up)

Q1: 90.2 (Got this by adding the two numbers of the upper half of data and dividing by 2)

Median/mean: 80.2 (Average of the data)

Q3: 85 (Rounded. Got this by adding the two numbers of the middle half of data and dividing by 2)

Answer:

A: 75

B: 80.2

C: 90.2

D: 85

E: 83

Yes, this makes sense since the data on the box-o-gram fall within the data given in the chart at the top of the worksheet.

5 0
3 years ago
I need help with this please​
Norma-Jean [14]

Step-by-step explanation:

r = 30/2 = 15

circumference = π*30= 94.2

7 0
3 years ago
Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2
Basile [38]

The Laplace transform of the given initial-value problem

y' 5y = e^{4t}, y(0) = 2 is  mathematically given as

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is  mathematically given as

&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}

\begin{aligned}&\text { Let } \frac{2 s-7}{(s+5)(s-4)}=\frac{a_{0}}{s-4}+\frac{a_{1}}{s+5} \\&\Rightarrow 2 s-7=a_{0}(s+s)+a_{1}(s-4)\end{aligned}

put $s=-s \Rightarrow a_{1}=\frac{17}{9}$

\begin{aligned}\text { put } s &=4 \Rightarrow a_{0}=\frac{1}{9} \\\Rightarrow \quad y(s) &=\frac{1}{9(s-4)}+\frac{17}{9(s+s)}\end{aligned}

In conclusion, Taking inverse Laplace tranoform

L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

Read more about Laplace tranoform

brainly.com/question/14487937

#SPJ4

6 0
2 years ago
How to convert decimals into fractions in simplest form
madam [21]
For example, lets take \frac{25}{100}

We need to first factor the numerator and denominator to find the common numbers which we can simplify it by.

\frac{25}{100} =  \frac{5 \times 5}{5\times 5\times 4}

If we divide by 5 x 5 on both the numerator and denominator because both of them have it in common, we will get the simplest form.

\frac{5 \times 5\div 5 \div 5}{5\times 5\times 4\div 5\div 5}  = \frac{1}{4}
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