Can someone help me wit da question listed in da picture?
2 answers:
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Answer:
Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:
Plug -2 for one of the slopes.
Divide by -2 to find the slope of our line.
Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:
Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:
Simplify and distribute:
Subtract 4 from both sides:
The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.
Answer:
Step-by-step explanation:
There are exponent rules I posted above that are being used here.
We have (3^-6)^-5
Since we have a power times a power, we multiply 6 and 5 to get -30. Look at the first example in the photo.
So, we're left with 3^-30.
If you look at the photo, there's a rule for negative exponents.
Take the inverse of the base number, so 3 in this case:
1 / 3
and then make the exponent positive after taking the inverse.
So, we should get 1 / 3^30
Hope this helps!
