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Anvisha [2.4K]
3 years ago
15

40 POINTS

Mathematics
1 answer:
NISA [10]3 years ago
6 0

Answer:

I can't understand how you wrote the question try writing it again so I can help

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Y = -2(x + 5)(x + 1)<br> Set the factor (x + 5) = 0 and solve
Harrizon [31]

Answer: x=-5

Step-by-step explanation:

x+5=0 \implies x=-5

7 0
2 years ago
A right triangle has a leg of 15 feet and a second leg of 24 feet. Find the length of the hypotenuse
Lorico [155]

Answer:

9

Step-by-step explanation:

-

4 0
3 years ago
Find the exact value of cos(arcsin(1/4)). For full credit, explain your reasoning.
Westkost [7]
First way
arcsin(1/4) means that 1/4 sin of the angle.

sin(α)=1/4
sin²α+cos²α=1
(1/4)²+cos²α=1
cos²α=1-1/16 =15/16
cosα=+/-(√15)/4

<span>Second way
</span>
sin(α)=1/4 =opposite leg/hipotenuse
cos(α)=adjacent leg/hypothenuse
adjacent leg =√(hypotenuse²- Opposite²)=√(16-1)=√15
cosα=+/-√15/4

For one value of sinα, possible 2 values of cosα.

5 0
3 years ago
In the late nineteenth century, the scientist Marie Curie performed experiments that led to the discovery of radioactive substan
gtnhenbr [62]

Answer:

Step-by-step explanation:

Half life is the time taken by a radioactive substance to reduce of half of its original size

If the half life of radium is 1600, this means that the original radioactive substance N0 have reduced to N0/2 after 1600 years

if we are given N0 = 1000grams

The amount of the substance that will remain after 1600 years will be N0/2 i.e 1000/2 = 500g

<em>Hence 500 grams of radium will be left after 600years</em>

5 0
3 years ago
a car purchased for $34,000 is expected to lose value, or depreciate, at a rate of 6% per year.using x for years and y for the v
Vika [28.1K]

Answer:

y = 34000(1-0.06) ^ t

After 7.40 years it will be worth less than 21500

Step-by-step explanation:

This problem is solved using a compound interest function.

This function has the following formula:

y = P(1-n) ^ t

Where:

P is the initial price = $ 34,000

n is the depreciation rate = 0.06

t is the elapsed time

The equation that models this situation is:

y = 34000(1-0.06) ^ t

Now we want to know after how many years the car is worth less than $ 21500.

Then we do y = $ 21,500. and we clear t.

21500 = 34000(1-0.06) ^ t\\\\log(21500/34000) = tlog(1-0.06)\\\\t = \frac{log(21500/34000)}{log(1-0.06)}\\\\t = 7.40\ years.

After 7.40 years it will be worth less than 21500

3 0
3 years ago
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