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MrRa [10]
3 years ago
11

If you wanted to create a sidewalk from your front door to the street, how much cement would you need if your sidewalk were goin

g to be the following dimensions

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

It’s simple you just multiply all three numbers 20*3*4=240

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Describe a real world situation that can be modeled by the equation 8.35x=4.25x+36.90
exis [7]
Lets reduce the equation.  

8.35x = 4.25x + 36.90 
8.35x - 4.25x = 36.90
4.10x = 36.90

X = 9 

1 bag a of assorted fruit cost $4.10 how much will it cost if I want to buy 9 bags of assorted fruit. 

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. One car traveled 210 miles and drove 20 mph hour faster than a second car drove 150 miles. If the cars were traveling for the
inn [45]

Answer:

The first car was traveling 70 mph, while the second was driving 50 mph.

Step-by-step explanation:

Set the cars as a proportion:

\frac{210}{x + 2}  =  \frac{150}{x}

X represents the speed of the second car. By cross multiplying, you get the following equation:

210x = 150(x + 20)

You solve by distributing 150 to get 210x = 150x + 3000.

Solving for x gets you 50.

That means the first car was going at 50 mph. Adding 20, you get 70 as the speed for the second car.

4 0
3 years ago
Hello can you please help me out on this question posted picture
pantera1 [17]
There are 3 possible outcomes of each game.

So, the tree will start with 3 leaves, and each leaf will further be divided into 3 leaves. Thus the total number of leaves in the tree diagram will be 3 x 3 = 9 leaves.

Option A correctly represent this situation. 
4 0
3 years ago
Let Upper A equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 4 2nd Row 1st Column 1 2nd Column 3
Anastaziya [24]

Answer:

See explanation

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]

B=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]

A. Find AB:

AB=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]\cdot \left[\begin{array}{cc}-2&1\\3&7\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+4\cdot 3&-2\cdot 1+4\cdot 7\\1\cdot (-2)+3\cdot 3&1\cdot 1+3\cdot 7\end{array}\right]=\left[\begin{array}{cc}16&26\\7&22\end{array}\right]

B. Find BA:

BA=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]\cdot \left[\begin{array}{cc}-2&4\\1&3\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+1\cdot 1&-2\cdot 4+1\cdot 3\\3\cdot (-2)+7\cdot 1&3\cdot 4+7\cdot 3\end{array}\right]=\left[\begin{array}{cc}5&-5\\1&33\end{array}\right]

C. Answers are not the same

D. Matrices multiplication is not commutastive in general, so

AB\neq BA

7 0
3 years ago
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