So, all you would do is use distribution. For example: D is .5(x+3) = -3(x-.5) you would do .5 times x+3, which equals .5x+ 1.5 So, .5x+1.5=-3x+1.5 because -3*x-.5 is -3x+1.5. Then, you would just get x by itself.
.5x+1.5=-3x+1.5 add 3 over to .5 = 3.5x; subtract 1.5 over to 1.5 = 0 now you have 3.5x = 0 divide by 3.5 to get x by itself and you get zero.
x=0
When you substitute it in, you should have them both equal to each other. I hope this helps. :)