Step-by-step explanation:
Denominators of both the fractions are 2x and (x - 5)
Therefore,
Lowest common denominator
![= 2x \times (x - 5) \\ = 2 {x}^{2} - 10x](https://tex.z-dn.net/?f=%3D%202x%20%20%5Ctimes%20%28x%20-%205%29%20%5C%5C%20%3C%2Fp%3E%3Cp%3E%3D%202%20%7Bx%7D%5E%7B2%7D%20%20-%2010x)
Answer:
0.520 < p < 0.591
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 542, \pi = \frac{301}{542} = 0.555](https://tex.z-dn.net/?f=n%20%3D%20542%2C%20%5Cpi%20%3D%20%5Cfrac%7B301%7D%7B542%7D%20%3D%200.555)
90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 - 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.52](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.555%20-%201.645%5Csqrt%7B%5Cfrac%7B0.555%2A0.445%7D%7B542%7D%7D%20%3D%200.52)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 + 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.59](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.555%20%2B%201.645%5Csqrt%7B%5Cfrac%7B0.555%2A0.445%7D%7B542%7D%7D%20%20%3D%200.59)
So the correct answer is:
0.520 < p < 0.591
Answer:
Huhhhh???
Step-by-step explanation:
Answer:
um I d K
Step-by-step explanation: