Answer:
<em>Proof below</em>
Step-by-step explanation:
<u>Exponential Grow Model</u>
The equation to model some time dependant event as an exponential is
![A=A_oe^{kt}](https://tex.z-dn.net/?f=A%3DA_oe%5E%7Bkt%7D)
Where Ao is the initial value, k is a constant and t is the time. With the value of Ao and k, we can compute the value of A for any time
We are required to find the time when the population being modeled doubles from Ao to 2 Ao. We need to solve the equation
![2A_o=A_oe^{kt}](https://tex.z-dn.net/?f=2A_o%3DA_oe%5E%7Bkt%7D)
Simplifying by Ao
![2=e^{kt}](https://tex.z-dn.net/?f=2%3De%5E%7Bkt%7D)
Taking logarithms in both sides
![ln2=lne^{kt}](https://tex.z-dn.net/?f=ln2%3Dlne%5E%7Bkt%7D)
By properties of logarithms and since lne=1
![ln2=kt\cdot lne=kt](https://tex.z-dn.net/?f=ln2%3Dkt%5Ccdot%20lne%3Dkt)
Solving for t
![\displaystyle t=\frac{ln2}{k}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20t%3D%5Cfrac%7Bln2%7D%7Bk%7D)
Hence proven