Answer:
3
Step-by-step explanation:
The correct answer is:
3
Explanation
review
△WXY~△GEF.
6
3
6
Y
X
W
2
1
2
F
E
G
What is the similarity ratio of △WXY to △GEF?
Simplify your answer and write it as a proper fraction, improper fraction, or whole number.
If two triangles are similar, their similarity ratio is the ratio between a side length in the first triangle and the corresponding side length in the second triangle.
solve
Look at the triangles.
6
3
6
Y
X
W
2
1
2
F
E
G
The similarity ratio of △WXY to △GEF is the ratio between a side length in △WXY and the corresponding side length in △GEF. So, the similarity ratio is
WX
EG
=
3
1
=3.
3(4x+3) simplified as an expression is: 12x+9
Answer:
5(m + 5) (m - 8)
Step-by-step explanation:
5m2- 15m- 200
Start by pulling 5 out.
5(m^2 - 3m - 40)
We consider all factors of 40
1 40
2 20
4 10
5 8
Based on the middle term we know that 5 and 8 are our best option.
5(m 5) (m 8)
We know the signs have to be one + and one - because a - * - = + and + * + = +
Since 5 - 8 would give us -3 we know that our answer is
5(m + 5) (m - 8)
Answer:
R3 <= 0.083
Step-by-step explanation:
f(x)=xlnx,
The derivatives are as follows:
f'(x)=1+lnx,
f"(x)=1/x,
f"'(x)=-1/x²
f^(4)(x)=2/x³
Simialrly;
f(1) = 0,
f'(1) = 1,
f"(1) = 1,
f"'(1) = -1,
f^(4)(1) = 2
As such;
T1 = f(1) + f'(1)(x-1)
T1 = 0+1(x-1)
T1 = x - 1
T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2
T2 = 0+1(x-1)+1(x-1)^2
T2 = x-1+(x²-2x+1)/2
T2 = x²/2 - 1/2
T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3
T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3
T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)
Thus, T1(2) = 2 - 1
T1(2) = 1
T2 (2) = 2²/2 - 1/2
T2 (2) = 3/2
T2 (2) = 1.5
T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)
T3(2) = 4/3
T3(2) = 1.333
Since;
f(2) = 2 × ln(2)
f(2) = 2×0.693147 =
f(2) = 1.386294
Since;
f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).
Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,
Since;
f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2
Finally;
R3 <= |2/(4!)(2-1)^4|
R3 <= | 2 / 24× 1 |
R3 <= 1/12
R3 <= 0.083
Answer:
(√2) / 3
Step-by-step explanation:
√(2/9) =√(2/3^2) =(√2)/3
