angle RUS with measure of 40 degrees and angle SUT with measure of y degrees If ray US is an angle bisector of ∠RUT, find m∠RUT.
2 answers:
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Answer:
Step-by-step explanation:
I've enclosed a graph to show you that there is one solution.
-4x + 3y = - 12
<u>- 2x + 3y = - 18</u><em><u> </u></em><em> </em>Subtract
-2x = 6 Divide by - 2
-2x/-2 = 6/-2
x = - 3
- 4x + 3y = - 12
-4(-3) + 3y = - 12
12 + 3y = - 12
3y = - 12 - 12
3y = - 24
3y/3 = - 24/3
y = - 8
Which is exactly what the graph shows.
You can tell immediately that this has 1 or more solutions just by looking at the number in front of x and y in each each equation.
It's always a good idea to graph a question like this one. Desmos is a pretty good tool to use if you don't have a graphing calculator.
The y's are the same so you are 1/2 way home in saying what you did.
The x's are different so that means you have at least 1 solution.
Q1. The answer is 
Q2. The answer is 1/16
![(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} = \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\ \\ (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } } \\ \\ ](https://tex.z-dn.net/?f=%28-64%29%20%5E%20%5Cfrac%7B-2%7D%7B3%7D%20%3D%28-1%2A%202%5E%7B6%7D%20%29%20%5E%20%5Cfrac%7B-2%7D%7B3%7D%3D%28-1%29%5E%20%5Cfrac%7B-2%7D%7B3%7D%20%2A%282%5E%7B6%7D%20%29%20%5E%20%5Cfrac%7B-2%7D%7B3%7D%20%5C%5C%5C%5Cx%5E%7B-a%7D%20%3D%20%20%5Cfrac%7B1%7D%7B%20x%5E%7Ba%7D%20%7D%20%5C%5C%5C%5C%28-1%29%5E%20%5Cfrac%7B-2%7D%7B3%7D%20%2A%282%5E%7B6%7D%20%29%20%5E%20%5Cfrac%7B-2%7D%7B3%7D%20%3D%20%5Cfrac%7B1%7D%7B%28-1%29%5E%20%5Cfrac%7B2%7D%7B3%7D%7D%20%2A%5Cfrac%7B1%7D%7B%282%5E%7B6%7D%29%5E%20%5Cfrac%7B2%7D%7B3%7D%7D%20%5C%5C%20%20%5C%5C%20%20%28x%5E%7Ba%7D%20%29%5E%7Bb%7D%3Dx%5E%7Ba%2Ab%7D%20%5C%5C%5C%5Cx%5E%7B%20%5Cfrac%7Ba%7D%7Bb%7D%20%3D%20%5Csqrt%5Bb%5D%7B%20x%5E%7Ba%7D%20%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A)
![\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } = \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%28-1%29%5E%20%5Cfrac%7B2%7D%7B3%7D%7D%20%2A%5Cfrac%7B1%7D%7B2%5E%7B6%2A%5Cfrac%7B2%7D%7B3%7D%7D%7D%20%3D%20%5Cfrac%7B1%7D%7B%20%5Csqrt%5B3%5D%7B%28-1%29%5E%7B2%7D%20%7D%20%7D%20%2A%20%5Cfrac%7B1%7D%7B%202%5E%7B4%7D%20%7D%20%3D%20%20%5Cfrac%7B1%7D%7B%20%5Csqrt%5B3%5D%7B1%7D%20%7D%20%2A%20%5Cfrac%7B1%7D%7B16%7D%20%3D%20%5Cfrac%7B1%7D%7B1%7D%20%2A%20%5Cfrac%7B1%7D%7B16%7D%3D%20%5Cfrac%7B1%7D%7B16%7D)
Q3. The answer is
Q2. The answer is 1/16
Q3. The answer is