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Juliette [100K]
2 years ago
13

Eight hundred tickets were sold for a theater production

Mathematics
1 answer:
yulyashka [42]2 years ago
3 0

Answer:

280 student tickets

520 adult tickets

Explanation:

I'm guessing this is the question you meant to ask:

Eight hundred tickets were sold for a movie production and the receipts for the performance wear $8600. The tickets for adults and students sold for $12.50 and $7.50, respectively. How many of each ticket were sold?

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Can somebody help me i have to drag the functions on top onto the bottom ones to match their inverse functions.
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1. x/5

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3 years ago
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9(u-2) + 1.5u=8.25
Colt1911 [192]

Answer:

u= 2.5

Step-by-step explanation:

Using BIDMAS

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5x + 45

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2 years ago
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Find d for the arithmetic series with S17=-170 and a1=2
Irina18 [472]
So, we know the sum of the first 17 terms is -170, thus S₁₇ = -170, and we also know the first term is 2, well

\bf \textit{ sum of a finite arithmetic sequence}\\\\&#10;S_n=\cfrac{n(a_1+a_n)}{2}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;----------\\&#10;n=17\\&#10;S_{17}=-170\\&#10;a_1=2&#10;\end{cases}&#10;\\\\\\&#10;-170=\cfrac{17(2+a_{17})}{2}\implies \cfrac{-170}{17}=\cfrac{(2+a_{17})}{2}&#10;\\\\\\&#10;-10=\cfrac{(2+a_{17})}{2}\implies -20=2+a_{17}\implies -22=a_{17}

well, since the 17th term is that much, let's check what "d" is then anyway,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;n=17\\&#10;a_{17}=-22\\&#10;a_1=2&#10;\end{cases}&#10;\\\\\\&#10;-22=2+(17-1)d\implies -22=2+16d\implies -24=16d&#10;\\\\\\&#10;\cfrac{-24}{16}=d\implies -\cfrac{3}{2}=d
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3 years ago
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