Answer:
The center is (5, -2) and the radius is 9/2
Step-by-step explanation:
The equation of a circle can be written by
(x-h) ^2 + (y-k)^2 = r^2
where (h,k) is the center and r is the radius
(x-5)^{2}+(y+2)^{2} = 81/4
( (x-5)^{2}+(y- -2)^{2} = (9/2)^2
The center is (5, -2) and the radius is 9/2
Answer:
There are 96 ways different 4 digit numbers which can be made from these 5 digits.
Step-by-step explanation:
There are 5 different digits. The first one must be
1 3 5 or 7
So you can have 4 for the first one. Now the zero can be put into the mix.
4 * 4 * 3 * 2
96
Answer:
10
Step-by-step explanation:
you take 2 times 5
Answer:
A. 2^11
Step-by-step explanation:
(They are basically asking what's 2^4 × 2^7, but with more words.)
I usually do each exponent individually:
2^4 is the same as 2 × 2 × 2 × 2 = 16 (or you could have read the text to figure that out)
2^7 is the same as 2 × 2 × 2 × 2 × 2 × 2 × 2 = 128
Then just multiply 128 and 16 to get 2,048, and see which option also gives you 2,048.
BUT, you can also:
(Combine the exponents together to get your answer. Just remember that if it's multiplication you add them, and if it's division you subtract them.)
2^4 × 2^7
4 + 7 = 11
2^11 (This equals 2,048 btw. You don't even have to check all the options to get the answer).
Hope this helps friend :)
The last part I learned from another user, while answering one of your other questions. I personally find this mind blowing, lol.
<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
