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2 years ago

7

Find the least common denominator for these fraction 4/8 and 1/4

1 answer:

babymother [125]2 years ago

8 0

Answer:

<h2><em><u>8</u></em></h2>

Step-by-step explanation:

As,

1/4 = (1×2)/(4×2) = 4/8

4/8 = (4×1)/(8×1) = 4/8

In both case,

The denominator 8 is least common multiple

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What is 5x to the second power

dolphi86 [110]

The answer is
25 because you multiply the base number twice

8 0

3 years ago

Solve the simultaneous equations<br> y = 9 - X<br> y = 2x2 + 4x + 6

kenny6666 [7]

Answer:

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

Step-by-step explanation:

Given the simultaneous equations

$y=9-x$

$y\:=\:2x^2\:+\:4x\:+\:6$

Subtract the equations

$y=9-x$

$-$

$\underline{y=2x^2+4x+6}$

$y-y=9-x-\left(2x^2+4x+6\right)$

$\mathrm{Refine}$

$x\left(2x+5\right)=3$

$\mathrm{Solve\:}\:x\left(2x+5\right)=3$

$2x^2+5x=3$ ∵ $\mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$2x^2+5x-3=3-3$

$\mathrm{Solve\:with\:the\:quadratic\:formula}$

$\mathrm{Quadratic\:Equation\:Formula:}$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\$

$x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$=\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{4}$

$=\frac{-5+7}{4}$

$=\frac{2}{4}$

$=\frac{1}{2}$

Similarly,

$x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{1}{2},\:x=-3$

$\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12$

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

3 0

3 years ago

The force on an area 16 m by 12 m is 24,000 N. What is the pressure per square meter?

Dmitrij [34]

Recall that
Pressure = Force ÷ Area

In this context we have,
Pressure = 24,000 ÷ (16 × 12)
= 24,000 ÷ 192
= 125 Pa

6 0

3 years ago

Read 2 more answers

6th Grade Math! Complete the function table and write the function rule. Please explain, since this is a written answer. Tysm!

ICE Princess25 [194]

Answer:

Its subtract 12.

Step-by-step explanation:

The first question mark is positive 6.

6-12= -6

The second question mark is -22.

Negative 10 minus 12 equals negative 22

Once you understand integers, it will be really easy. I was in 6th grade last year.

4 0

3 years ago

What is this equation of this line?

lisov135 [29]

The equation of the line is y=2/3x + 0

Explanation: The y intercept (where the line crosses the y axis) is 0, and the slope is 2/3 (up two and 3 to the right)

7 0

3 years ago