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3 years ago

I don't know how to do "log"... can someone tell me what it is and how to do it

Mathematics

1 answer:

Otrada [13]3 years ago

4 0

There are a few meanings, well it like when u log in to a website or when u sign in (register in/login)

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Please help me with this plz

NeX [460]

Answer:

A yes

B yes

C No

D No

Step-by-step explanation:

If it is a function then the first number in the ordered pair is use only one time.

5 0

2 years ago

two angles form a linear pair. the measure of one angle is 1/4 the measure of the other angle. find the measure of each angle

vlabodo [156]

The sum of the angles equals 180
therefore
x+(1/4x)=180
1 1/4 x = 180
x=180/ 1 1/4
x=144
1/4 x =1/4(144)=36

4 0

3 years ago

Kelly walks 0.7 mile to school. write an inequality using <, >, = to compare the distances they walk to school. I need hel

Igoryamba

One inequality is 0.8>0.7>0.6. I hope it

8 0

3 years ago

9(x+3)=4x-3 I need to use the distributive property to solve

algol [13]

Answer:

x= 6

Step-by-step explanation:

8 0

3 years ago

I have nooooo clue, please help

Aleksandr-060686 [28]

Answer:

case a) $x^{2}=3y$ ----> open up

case b) $x^{2}=-10y$ ----> open down

case c) $y^{2}=-2x$ ----> open left

case d) $y^{2}=6x$ ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

$y=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

$x=a(y-k)^{2}+h$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

$x^{2}=3y$

$y=(1/3)x^{2}$

$a=(1/3)$

$a>0$

therefore

The parabola open up

case b) we have

$x^{2}=-10y$

$y=-(1/10)x^{2}$

$a=-(1/10)$

$a$

therefore

The parabola open down

case c) we have

$y^{2}=-2x$

$x=-(1/2)y^{2}$

$a=-(1/2)$

$a$

therefore

The parabola open to the left

case d) we have

$y^{2}=6x$

$x=(1/6)y^{2}$

$a=(1/6)$

$a>0$

therefore

The parabola open to the right

3 0

3 years ago