Diagonal of the parallelogram divides the parallelogram in to two equal areas.
So area of parallelogram = 2(area of triangle)
According to the given diagram,
AB= 8, AD = 5 and BD = 11
So according to the Heron's formula,
Area of triangle = 
and a, b and c are the three sides of the triangle
Area of triangle ABD =
So, area of parallelogram ABCD = 2(area of triangle ABD)
area of parallelogram ABCD = 2 (18.33)
area of parallelogram ABCD = 36.66
area of parallelogram ABCD = 36.7 sq. units
C is the answer to that question i think
X - y = 3
x + y = 13
Adding both equations
2x = 16
x = 8
y = 5
Answer is below in the picture:-
(From the problem, we know (triangle)ABC (round of equal of) (triangle)A'B'C'. So, <A'B'C' = <ABC {the properties of congruent triangles}. So, ray BC is the angle, bisector of angle ABA')
I hope it helps.
Set up an equation
1/2x+6=2/3x
Take all x's to one side & constants to other
1/2x-2/3x=-6
Subtract by getting a common denominator
-1/6x=-6
Divide both sides by -1/6
x=36