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2 years ago

A baker bought 4 gallons oficing to decorate cakes. He uses 4 % cups

Mathematics

1 answer:

sergejj [24]2 years ago

5 0

25 cakes can be completely decorated using 4 gallons of icing.

Step-by-step explanation:

Given:

4 gallons of icing

16 cups =1 gallon

No. of icing cups = $4\times16$ cups

=64 cups

No. of cups required to decorate and frost a cake= 4% of total no. of icing cups

= $\frac{(4\times64)}{100}$

= 2.56

2.56 cups of icing is required to decorate each cake.

Maximum no. of cakes decorated = $\frac{ (64\times1)}{2.56}$

= 25

25 cakes can be completely decorated using 4 gallons of icing.

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Celeste has a garden that has a length of 15x and a width of 3x+ 5 feet. Write a polynomial that represents the perimeter of the

maw [93]

36x+10 feet
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2 years ago

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Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1]

Alekssandra [29.7K]

$\green{\large\underline{\sf{Solution-}}}$

Given expression is 

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can be rewritten as

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We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

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can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

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$\rm \: = \: \dfrac{4}{24}$

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Hence, 

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

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2 years ago

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Answer:

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