2 years ago

Sorry if it is not clear the question asks, Two squares of side x cm are removed from a square of side 3x cm as shown

1 answer:

5 0

$(3x)^2-2\cdot x^2=9x^2-2x^2=7x^2\\\\
\frac{7x^2}{9x^2}=\boxed{\frac{7}{9}}$

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zhuklara [117]

Let

x---------> the thickness of the frame in feet

At-------> Area of the mirror and the frame in square feet

we know that

$At=19.25ft^{2}$ ------> equation $1$

$At=(3+2x)*(5+2x)\\ At=3*5+3*2x+5*2x+2x*2x\\ At=15+6x+10x+4x^{2} \\ At=4x^{2} +16x+15$ --------> equation $2$

equate equation $1$ and equation $2$

$19.25=4x^{2} +16x+15\\ 4x^{2} +16x+15-19.25=0\\ 4x^{2} +16x-4.25=0$

therefore

the answer is the option

$C. 4x2 + 16x - 4.25 = 0$

5 0

3 years ago

stiks02 [169]

Answer:

Step-by-step explanation:

+ and - cancel. We have 5 + and 3 - so that leaves us with 2 + so the answer is +2.

5 0

3 years ago

Leona [35]

I think it would be (x+7)/7

4 0

2 years ago

Elena L [17]

follow the above steps may be it's right

6 0

3 years ago

pentagon [3]

The correct answer should be tax

5 0

3 years ago