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xz_007 [3.2K]
3 years ago
9

What is 21/36 in simplest form and in decimal form?

Mathematics
2 answers:
KiRa [710]3 years ago
4 0
The answer for simplifying the fraction would be 7/12 and in decimal form 7/12 to decimal would be 0.583333
vazorg [7]3 years ago
4 0
 21/36 is 0.58 in decimal form.
21/26 is 7/12.

Hope this helps,
Tiara
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A bag of potatoes weighs 15 pounds. How many kilograms is this?​
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Answer:

6.8 kg

Step-by-step explanation:

1 pound = 0.4536 kg

15(0.4536) = 6.804

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3 years ago
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topjm [15]
No she is not correct
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3 years ago
A hovercraft takes off from a platform it’s height (in meters), x seconds after takeoff, is modeled by
yulyashka [42]

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Answer:

  81 m

Step-by-step explanation:

Since x is seconds after takeoff, the value of x at takeoff is 0. You are being asked to find H(0).

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8 0
2 years ago
I'll mark the best or the first as brainliest.
FinnZ [79.3K]

Answer:

<em><u>Here</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>error</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em>

<em><u>\pi {r}^{2}</u></em>

<em><u>It</u></em><em><u> </u></em><em><u>should</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>been</u></em><em><u> </u></em><em><u>,</u></em>

<em><u>2\pi {r}^{2}</u></em>

Step-by-step explanation:

<em><u>Corrected</u></em><em><u> </u></em><em><u>formula</u></em><em><u>:</u></em>

<em><u>2\pi  {r}^{2}  + 2\pi rh</u></em>

<em><u>= 2\pi ({5}^{2})  + 2\pi(5)(10.6)</u></em>

<em><u>= 50\pi + 106\pi</u></em>

<em><u>= 156\pi</u></em>

<em><u>= 489.84 {yd}^{2}</u></em>

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6 0
3 years ago
Express p in terms of q if
Irina-Kira [14]

p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)

q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}

8 0
2 years ago
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