The answer is 69/100 because u have to turn the denominator to become common denominator
Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as
Since the arithmetic mean is the sum of the values, divided by how many they are, we have
So, the mean of 11 consecutive integers is the 6th integer.
Step-by-step explanation:
It's answer is x_> -27 by using inequality rule
Step-by-step explanation:
Explanation:
The trick is to know about the basic idea of sequences and series and also knowing how i cycles.
The powers of i will result in either: i, −1, −i, or 1.
We can regroup i+i2+i3+⋯+i258+i259 into these categories.
We know that i=i5=i9 and so on. The same goes for the other powers of i.
So:
i+i2+i3+⋯+i258+i259
=(i+i5+⋯+i257)+(i2+i6+⋯+i258)+(i3+i7+⋯+i259)+(i4+i8+⋯+i256)
We know that within each of these groups, every term is the same, so we are just counting how much of these are repeating.
=65(i)+65(i2)+65(i3)+64(i4)
From here on out, it's pretty simple. You just evaluate the expression:
=65(i)+65(−1)+65(−i)+64(1)
=65i−65−65i+64
=−65+64
=−1
So,
i+i2+i3+⋯+i258+i259=-1
Let us use x as the cost before Chet would apply a $25 gift certificate. Based on the problem, we can see that the original cost of the product cannot be more than 75 which means that it can be equal to 75 or less than 75. We can actually express the inequality as x< or = 75 since we are looking for the cost before Chet applied the $25 gift certificate. This means that we do not need to add in the 25 yet since the question asks for the cost before the application of the discount. - Credits, <span>Taskmasters and Hegans</span>
