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shtirl [24]
3 years ago
11

Which of the following does not describe a rigid motion transformation?

Mathematics
2 answers:
guapka [62]3 years ago
8 0

The answer is C, dilating a figure by a scale factor of 1/4.

sesenic [268]3 years ago
3 0
<h2>Answer:</h2>

The transformation which do not describe a rigid motion transformation is:

           Option: C

   C. dilating a figure by a scale factor of 1/4

<h2>Step-by-step explanation:</h2>

Rigid motion transformation is a transformation in which the shape and size of the figure is preserved i.e. it remains the same.

A)

Translating a figure 5 units right.

We know that in the translation transformation the shape and size of the figure remains the same only the location of points are changed.

B)

Rotating a figure 90 degrees.

In rotation the shape and size is preserved.

Hence it is a rigid transformation.

C)

dilating a figure by a scale factor of 1/4

This is not a rigid transformation because the size of the figure is changed.

since the scale factor is less than 1.

Hence, the transformation is a reduction of the original figure.

D)

reflecting a figure across the x-axis.

The reflection is also a rigid transformation.

since it preserves the shape and size of the object.

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A video game costs $45.99. It is 45% off today at the store. What is the sale price of the video game?
stepan [7]

Answer:

the sale price of the video game after discount is 25.29

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Step-by-step explanation:

5 0
3 years ago
The amount of time (t) in minutes it takes Jeff to mow an average sized yard is related to (n) the number of yards he mows. The
Sveta_85 [38]

Answer:

Jeff mows 9 yards of lawn in 30 minutes

Step-by-step explanation:

The equation that models the amount of time (t) in minutes it takes Jeff to mow an average sized yard is t=2n+12, where n is the number of yards he mows.

To find the number of yards Jeff mows in 30 minutes, we set the equation to 30 and solve for n.

\implies 2n+12=30

Add -12 to both sides:

\implies 2n=30-12

\implies 2n=18

Divide both sides by 2

\implies \frac{2n}{2}=\frac{18}{2}

\implies n=9

Hence Jeff mows 9 yards of lawn in 30 minutes.

4 0
3 years ago
3q - 16q = 7 + 2(-89 – 3)
levacccp [35]

Answer:

q = 177/13

Step-by-step explanation:

3q - 16q = 7 + 2(-89 – 3)

-13q = 7 + 2(-92)

-13q = 7 - 184

-13q = -177

q = (-177)/(-13)

q = 177/13

3 0
3 years ago
What is the power of 10 the number 1.973 must be multiplied by to get 19,730,000
disa [49]

Answer: Is It 40? I cant really do this on paper sorry too many multiplication steps

Step-by-step explanation:

Sorry im just very confused but I tried my best

4 0
3 years ago
Read 2 more answers
A car insurance company has determined that 8% of all drivers were involved in a car accident last year. Among the 15 drivers li
svetlana [45]

Answer:

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

Step-by-step explanation:

For each driver surveyed, there are only two possible outcomes. Either they were involved in a car accident last year, or they were not. This means that we solve this problem using binomial probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

15 drivers are randomly selected, so n = 15.

A success consists in finding a driver that was involved in an accident. A car insurance company has determined that 8% of all drivers were involved in a car accident last year.  This means that \pi = 0.08.

What is the probability of getting 3 or more who were involved in a car accident last year?

This is P(X \geq 3).

Either less than 3 were involved in a car accident, or 3 or more were. Each one has it's probabilities. The sum of these probabilities is decimal 1. So:

P(X < 3) + P(X \geq 3) = 1

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{15,0}.(0.08)^{0}.(0.92)^{15} = 0.2863

P(X = 1) = C_{15,1}.(0.08)^{1}.(0.92)^{14} = 0.3734

P(X = 2) = C_{15,2}.(0.08)^{2}.(0.92)^{13} = 0.2273

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2863 + 0.3734 + 0.2273 = 0.887

Finally

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.887 = 0.113

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

5 0
3 years ago
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