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3 years ago

10

A student needs at least seven hours of sleep each night the student goes to bed at 11 pm and wakes up before 6:30 am is the stu

dents getting enough sleep? Write an and equally for the numbers of hours of sleep the student gets each night.

1 answer:

Fittoniya [83]3 years ago

6 0

the student is getting a full 7 hours of sleep if they wake up at 6 a.m. and if they go to sleep at 11

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A pair of shoes was discounted 20% after the discount, the cost of the shoes is $100 what was the initial price

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It is $80 dollars I think

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A $120.00 pair of shoes at your nearby department store is marked up 4% and then is offered at 45% off. If sales tax is 13%, wha

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$26

Step-by-step explanation:

0.8(X - 3) = 18.4

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3 years ago

Jaxson is throwing a pizza party. He has 1\tfrac{1}{4}1 4 1 pounds of cheese available and he needs \tfrac{1}{8} 8 1 pound o

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Answer:

10 pizzas

Step-by-step explanation:

Jaxson is throwing a pizza party. He has 1\tfrac{1}{4}1 4 1 pounds of cheese available and he needs \tfrac{1}{8} 8 1 pound of cheese to make each pizza. How many pizzas can he make?

We can interprete the above question as:

1/8 pounds of cheese = 1 pizza

1 1/4 pounds of cheese = x pizzas

Cross Multiply

1/8 × x = 1 1/4 × 1

x = 1 1/4 ÷ 1/8

x = 5/4 ÷ 1/8

x = 5/4 × 8/1

x = 10 pizzas

x = 10 pizzas

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3 years ago

Is -128/5 a terminating or repeating decimal??

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Answer:

terminating

Step-by-step explanation:

-128 / 5 = -25.6

-25/6 is terminating because it has an end. a repeating decimal on the other hand goes on forever, like 3.33333...

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3 years ago

There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl

Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0

3 years ago