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Sveta_85 [38]
3 years ago
14

I need to know this please

Mathematics
2 answers:
anyanavicka [17]3 years ago
4 0
The answer is C



hope this helps :))
jenyasd209 [6]3 years ago
3 0
The answer should be C

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Angle math Hw. Pls help
timurjin [86]

Answer:

x = 45°

Step-by-step explanation:

We can tell that "x + 115" and 160° are vertically opposite angles, which means that they are equal. (Refer to image)

⇒ x + 115 = 160

⇒ x = 160 - 115

⇒ x = 45°

Learn more about vertically opposite angles: brainly.com/question/68367

<h3>Image:</h3>

6 0
2 years ago
Read 2 more answers
A particle moves along a line with a velocity v(t)=t2−t−6, measured in meters per second. Find the total distance the particle t
ahrayia [7]

Answer:

10.67 m

Step-by-step explanation:

Velocity is given as;

v(t) = t² − t − 6

To get the distance, we will integrate the velocity equation.

x(t) = ∫v(t) = (t³/3) - (t²/2) - 6t

Thus, from t=0 seconds to t=4 seconds., we have;

(t³/3) - (t²/2) - 6t between 0 and 4.

Thus;

Total Distance = [(4³/3) - (4²/2) - 6(4)] - [(0³/3) - (0²/2) - 6(0)]

Total distance = (64/3) - 8 - 24 = -10.67 m

Distance can't be negative and so we take the absolute value which is 10.67 m

7 0
3 years ago
How many ways can you select pants, a shirt, and shoes if you have 5 pants, 7 shirts, and 3 pairs of shoes to choose from
Delicious77 [7]
5*7*3
35*3= 105
105 different ways
8 0
4 years ago
Alexia designed a logo 2 inches wide and 1.5 inches tall to be used on her school's notebooks. The school wants the logo on the
Xelga [282]

If the original logo is 2 inches wide and the logo has to be 8 inches wide, then the new logo will be 4 times larger. Therefore, we have to multiply 1.5 by 4 to get our new height.

1.5 x 4 = 6 inches tall.

Hope this helped!

5 0
2 years ago
given a soda can with a volume of 15 and a diameter of 2, what is the volume of a cone that fits perfectly inside the soda can (
Paul [167]

Answer:

sorry but can you answer my question first

Step-by-step explanation:

brainly.com/question/17587885

7 0
4 years ago
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