The power in C is correct. it is x / 37 So B,C and D all have the correct power. Now you must turn to the base. You are talking about a half life so what is raised to the the correct power must be 1/2
That eliminates D and C both.
A is gone because it has the wrong power.
B <<<< the first part of the question's answer.
Now we will answer the 6 days part.
y = 477 * (1/2) ^(x / 37)
x = 6
y = 477 * (1/2)^ (6/37)
y = 477 * (1/2)^ (0.162 [repeating] )
y = 477 * 0.8397
y = 426.2876 which is confirmed by the answer given. <<<< second answer.
Answer: third option
Step-by-step explanation:
To solve the problem you must apply the proccedure shown below:
- Descompose the numerator and the denominator of the given fraction into its prime numbers:
Then you can rewrite:
Then:
Therefore, the answer is: 
Answer:
The general limit exists at <em>x</em> = 9 and is equal to 300.
Step-by-step explanation:
We want to find the general limit of the function:
By definition, a general limit exists at a point if the two one-sided limits exist and are equivalent to each other.
So, let's find each one-sided limit: the left-hand side and the right-hand side.
The left-hand limit is given by:
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Since the given function is a polynomial, we can use direct substitution. This yields:
Evaluate:
Therefore:
The right-hand limit is given by:
Again, since the function is a polynomial, we can use direct substitution. This yields:
Evaluate:
Therefore:
Thus, we can see that:
Since the two-sided limits exist and are equivalent, the general limit of the function does exist at <em>x</em> = 9 and is equal to 300.
Answer:
Step-by-step explanation:
The diagram of the triangles are shown in the attached photo.
1) Looking at ∆AOL, to determine AL, we would apply the sine rule
a/SinA = b/SinB = c/SinC
21/Sin25 = AL/Sin 105
21Sin105 = ALSin25
21 × 0.9659 = 0.4226AL
AL = 20.2839/0.4226
AL = 50
Looking at ∆KAL,
AL/Sin55 = KL/Sin100
50/0.8192 = KL/0.9848
50 × 0.9848 = KL × 0.8192
KL = 49.24/0.8192
KL = 60
AK/Sin25 = AL/Sin 55
AKSin55 = ALSin25
AK × 0.8192 = 0.4226 × 50
AK = 21.13/0.8192
AK = 25.8
2) looking at ∆AOC,
Sin 18 = AD/AC = 18/AC
AC = 18/Sin18 = 18/0.3090
AC = 58.25
Sin 85 = AD/AB = 18/AB
AB = 18/Sin85 = 18/0.9962
AB = 18.1
To determine BC, we would apply Sine rule.
BC/Sin77 = 58.25/Sin85
BCSin85 = 58.25Sin77
BC = 58.25Sin77/Sin85
BC = 58.25 × 0.9744/0.9962
BC = 56.98
Answer:
i think the answer is b
Step-by-step explanation:
