Children’s tickets are $4, adult tickets are $14
Explanation:
4a+6c=80
If they made $4 more dollars on the second day than the first by selling one extra child ticket then we know a child’s ticket is $4 per ticket.
4a+6*4=80
4a+24=80
4a=56
14=a
So each adult ticket costs $14.
You can check by filling in $14 and $4 for each equation.
4*14+6*4=80
4*14+7*4=84
Answer:
165
Step-by-step explanation:
First, m<UTS=m<UTV+m<VTS by Angle Addition Postulate. Then, you substitute all the values that you provided for the angles. 15x+15=x+15+140. You then solve for x.
15x+15=x+155
14x=140
x=10
You then plug back in 10 for X in the value of m<UTS. 15(10)+15=165
Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?
Answer:
A
Step-by-step explanation:
6x+3y=33 <=> 2x+y=11<=>4x+2y=22 (1)
4x+y=15 (2)
(1)-(2) <=> y=7
Numbers are 416, 417 and 418
<u>Step-by-step explanation:</u>
Step 1:
Let the numbers be x, x + 1 and x + 2. Given that their sum is 1251.
⇒ x + x + 1 + x + 2 = 1251
⇒ 3x + 3 = 1251
⇒ 3x = 1248
⇒ x = 416
Step 2:
Find the other numbers.
⇒ x + 1 = 417 and x + 2 = 418
