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2 years ago

PLZ ANSWER <3

Mathematics

2 answers:

Oksi-84 [34.3K]2 years ago

8 0

Answer:

hang on give me a sec to edit this

it is.

Alchen [17]2 years ago

6 0

Mean and standerd deviation to standardizing a value Other words to find the Z score , in a normally distributed data, the value of mean represent 50% of the population

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(-9)-(-13)+(3)<img src="https://tex.z-dn.net/?f=" id="TexFormula1" title="" alt="" align="absmiddle" class="latex-formula">

Cloud [144]

Hi,

$( - 9) - ( - 13) + (3) \\ - 9 - ( - 13) + (3) \\ - 9 + 13 + 3 = 7$

Hope this helps.
r3t40

4 0

3 years ago

Investments increase exponentially by

Blizzard [7]

Using an exponential function, it is found that you would have $10,240 after 18 years.

<h3>What is an exponential function?</h3>

An increasing exponential function is modeled by:

$A(t) = A(0)(1 + r)^t$

In which:

A(0) is the initial value.

r is the growth rate, as a decimal.

Considering the initial value of $2,500, and the growth rate of 60% every 6 years, the equation is given by:

$A(t) = 2500(1.6)^\frac{t}{6}$

Hence, after 18 years, the amount is given by:

$A(18) = 2500(1.6)^\frac{18}{6} = 10240$

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

5 0

2 years ago

5/6÷2/7 in the simplest form

pickupchik [31]

Answer:

2 11/12 mixed number

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A rectangle has area x^3+3x^2−18x\ in.^2

madam [21]

You can download answer here

tinyurl.com/wtjfavyw

3 0

3 years ago

At an effective annual interest rate of i > 0, each of the following two sets of payments has present value K: (i) A payment

IgorLugansk [536]

Answer:

The present value of K is, $K=251.35$

Step-by-step explanation:

First of all, we need to construct an equation system, so

$(1)K=\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}$

$(2)K=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}$

Then we equalize both of them so we can find $i$

$(3)\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}$

To solve it we can multiply $(3)*(1+i)^{4}$ to obtain $(1+i)^{4}*(\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}})$ , then we have $225(1+i)^{2}+225=169(1+i)^{3}+169(1+i)^{2}$ .

This leads to a third-grade polynomial $169i^{3}+451i^{2}+395i-112=0$ , after computing this expression, we find only one real root $i=0.2224$ .

Finally, we replace it in (1) or (2), let's do it in (1) $K=\frac{169}{(1+0.2224)} +\frac{169}{(1+0.2224)^{2}}\\\\K=251.35$

8 0

3 years ago