Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
Rounding to the nearest tenth means rounding to the decimal place directly to the right of the decimal.
The rules of rounding are fairly simple. If the number to the right of the number you are rounding is greater than or equal to 5, you round up. If the number to the right is less than 5, you round down.
Let's take a look at the number 12.345.
First, round to the hundredths place. The number right before the 4 is 5, so we round up. This gives us the number 12.35.
Next, we have to round to the tenths place. The number to the right of the 3 is 5, so we round up as well. This gives us the number 12.4.
Answer: 12.4
Answer:
4
Step-by-step explanation:
The area is 16, and you know that it's 2 sides u need to multiply
The perimeter is 16, and you know that you need to add up all the sides
So....
A = b * h
A = 4 * 4
A = 16 CORRECT
And....
P = S + S + S + S ( s = sides)
P = 4 + 4 + 4 + 4
P = 16 CORRECT
Hope this helped!
Have a supercalifragilisticexpialidocious day!
P would equal -3/7
Hope it helps!
The distance between two points (x₁,y1),(x₂,y₂) is d
For the given problem we have
<span>W(1,8),X(7,8),Y(4,5), and Z(1,2)
The length of WY = </span>
= 3√2
The length of WX =
= 6
The length of WZ =
= 6
The length of XY = <span><span>
= 3√2
</span>The length of ZY = </span><span>
= 3√2
∴ WX = WZ ⇒⇒⇒ proved
XY = ZY ⇒⇒⇒ proved
WY = WY ⇒⇒⇒ reflexive property
∴ Δ</span><span>WYZ is congruent to ΔWYX by SSS method</span>
