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Sloan [31]
4 years ago
9

Place each algebraic expressions next to its corresponding verbal description

Mathematics
2 answers:
nika2105 [10]4 years ago
7 0

(a)

x cubed is

=x^3

5 times the cube of x is

=5x^3

4 times x is

=4x

the quotient of 4 times x and 3 is

=\frac{4x}{3}

so,

the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is

=5x^3-\frac{4x}{3}..........Answer

(b)

5 times cube of x is

=5x^3

5 times cube of x divided by 4 times x is

=\frac{5x^3}{4x}..........Answer

(c)

difference of 5 times x cube and 4 is

=5x^3 -4

so,

the quotient of the difference of 5 times x cube and 4 and x is

=\frac{5x^3-4}{x}...........Answer

(d)

difference of 5 times x and 4 is

=5x-4

so,

the cube of the difference of 5 times x and 4 is is

=(5x-4)^3............Answer


Nastasia [14]4 years ago
4 0

(a) the difference of 5 times the cube of x cubed and the quotient of 4 times  x and 3

5 times the cube of x cubed is  5x^3

he quotient of 4 times  x and 3 is \frac{4x}{3}

The difference is  5x^3- \frac{4x}{3}

(b) 5 times the cube of x divided by 4 times x

5 x^3 divide by 4x. So expression is \frac{5x^3}{4x}

(c) the quotient of the difference of 5 times x cubed and 4 and x

the difference of 5 times x cubed and 4 is  5x^3-4

The quotient of 5x^3-4 and x  is  \frac{5x^3-4}{x}

(d) the cube of the difference 5 times x  and 4

difference 5 times x  and 5 is 5x -4

the cube of (5x-4) is (5x-4)^3

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gulaghasi [49]

For the given equation,4x²−y²−24x−4y+28=0.The center is (h,k)=(3,−2), vertex (h+a,k)=(4,−2) and (h−a,k)=(2,−2), foci is (h+c,k)=(5.23,−2) and (h−c,k)=(0.77,−2)

<h3>What is the equation?</h3>

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

It is given that, the equation of the hyperbola is,

4x²−y²−24x−4y+28=0

Comparing the equation with the standard equation we get,

Center (h,k)=(3,−2)

Vertex (h+a,k)=(4,−2) and (h−a,k)=(2,−2)

Foci (h+c,k)=(5.23,−2) and (h−c,k)=(0.77,−2)

Asymptotes y=2x−8 and y=−2x+4

Thus, for the given equation,4x²−y²−24x−4y+28=0.The center is (h,k)=(3,−2), vertex (h+a,k)=(4,−2) and (h−a,k)=(2,−2), foci is (h+c,k)=(5.23,−2) and (h−c,k)=(0.77,−2)

Learn more about the equation here,

brainly.com/question/10413253

#SPJ2

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