Question

Can someone please tell me what I'm doing wrong? I think I know how to do quadratic formula, and I know all the steps, but the last step where you solve after everything is in it's place really confuses me. I put some pictures of what I did and What the question was.
*most helpful answer will be the brainliest!**

Answer 1

The pic above shows answer




Nvm it tho now

Answer 2

Okay, so first you set equal to 0:
$6-6x^{2}=3x\\-6x^{2}-3x+6=0$

Next simplify the equation so that the leading coefficient is positive:
$\frac{-6x^{2}-3x+6}{-3}=\frac{0}{3}\\2x^{2}+x-2=0$

Looking at the quadratic equation you can't easily simplify it, so plug it into the quadratic equation and simplify:
$x=\frac{-b\ -+\ \sqrt{b^{2}-4ac}}{2a}\\\\x=\frac{-(1)\ -+\ \sqrt{(1)^{2}-4(2)(-2)}}{2(2)}\\\\x=\frac{-1\ -+\ \sqrt{1+16}}{4}\\\\x=\frac{-1\ -+\ \sqrt{17}}{4}*\frac{-1}{-1}\\\\x=\frac{1\ -+\ \sqrt{17}}{-4},\ or\ B.$


I noticed a couple mistakes in your work, so if you want me to I can explain them in the comments section :)