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gregori [183]
3 years ago
12

Colin wants to set up an aquarium.. He already has a tank, but needs to purchase fish, filters, and plants. If the cost of the f

ish
is $84.79, the filters usually cost $60.45 but Colin finds them on sale for $44.75, and the cost of the plants is $18.66, determine
how much of Colin's $488.85 savings will be used to set up his aquarium.
a $289.81
Mathematics
2 answers:
ahrayia [7]3 years ago
7 0

Answer:

340.65

Step-by-step explanation: Add 84.79+44.75+18.66=148.2

148.2-$488.85= 340.65

Kisachek [45]3 years ago
7 0

Answer:

$148.2

Step-by-step explanation:

He needs to purchase fish, filters, and plants

Cost of the fish: $84.79

Cost of the filters: $44.75

Cost of the plants: $18.66

Total cost: $84.79 + $44.75 + $18.66 = $148.2

Despite how much Colin saved, he spent $148.2 to set up an aquarium.

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The rectangle below has an area of 144x4 square meters and a width of 12x meters. What is the length of the rectangle?
Alex777 [14]
<h3>The length of rectangle is 12x³ metres .</h3>

As we know that

♦ Area of rectangle = Length × breadth

Substituting known values ,

⇒ 144x⁴ = 12x ( Length )

⇒ 144x⁴ / 12x = Length

⇒ 12x³ = Length

⇒ Length = 12 x³

7 0
3 years ago
Multiply and simplify. Assume that all variables are positive.
Liula [17]

Answer:

2x^{4} \sqrt{6x} should be the answer. Free points, why not?

Step-by-step explanation:

1. \sqrt{3x^{6} }*\sqrt{8x^{3}}

2.\sqrt{24x^{9} }

3. \sqrt{4} *\sqrt{x^{8} } *\sqrt{6x}

4. 2x^{4} \sqrt{6x}

7 0
3 years ago
Someone help please.
AnnyKZ [126]

Answer:

Translation (the +5)

Dilation (the x 4)

Compression (the 3 to 1/3, and the x to 2-x)

Step-by-step explanation:

Brainliest, please!

5 0
3 years ago
What the recursive formula for the sequence
klemol [59]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a_n=2-5(n-1)\implies a_n=\stackrel{\stackrel{a_1}{\downarrow }}{2}+(n-1)(\stackrel{\stackrel{d}{\downarrow }}{-5})


so, we know the first term is 2, whilst the common difference is -5, therefore, that means, to get the next term, we subtract 5, or we "add -5" to the current term.

\bf \begin{cases} a_1=2\\ a_n=a_{n-1}-5 \end{cases}


just a quick note on notation:

\bf \stackrel{\stackrel{\textit{current term}}{\downarrow }}{a_n}\qquad \qquad \stackrel{\stackrel{\textit{the term before it}}{\downarrow }}{a_{n-1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current term}}{a_5}\qquad \quad \stackrel{\textit{term before it}}{a_{5-1}\implies a_4}~\hspace{5em}\stackrel{\textit{current term}}{a_{12}}\qquad \quad \stackrel{\textit{term before it}}{a_{12-1}\implies a_{11}}

8 0
4 years ago
Angles A and B are complementary. Angle A has a measure of 2X - 8. Angle B
harkovskaia [24]

Answer:

Step-by-step explanation:

180 = 2x-8 + 36

152 = 2x

76 = x

now plug it into the given expression

∠A = 2x-8

∠A = 2(76) -8

∠A = 152-8

∠A = 144 °

:)

6 0
3 years ago
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