Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error of the interval is given by:
In this problem, we have that:
99.5% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Least to Greatest: -3.05 1/2, -.875 1/3, & .40
Answer:
here
Step-by-step explanation:
The answer to this problem is
all real numbers except for 4. When looking at this function, one can see that most numbers are possible. But, the only number that won't be possible is four. That's because the fraction
will always equal something greater than or less than zero. Since it's never going to equal zero, and since there is already a 4, that means that the range of this function is
all real numbers except for 4.
