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Alla [95]
3 years ago
7

PLSSS HELP AND EXPLAIN YOUR ANSWER!! :)

Mathematics
1 answer:
Vilka [71]3 years ago
6 0

t = 14.9 years

Solution:

Given data:

I = $688.38, P = $550, r = 8.4%, t = ____ years

Simple interest formula:

$I=\frac{Prt}{100}

$688.38=\frac{550 \times 8.4  \times t}{100}

Switch the sides.

$\frac{550 \times 8.4  \times t}{100}=688.38

Multiply by 100 on both sides.

$\frac{100 \times 550 \times 8.4 t}{100}=688.38  \times 100

$550 \times 8.4 t=68838

4620 t=68838

Divide by 4620 on both sides.

$\frac{4620 t}{4620}=\frac{68838}{4620}

$t=\frac{149}{10}

t = 14.9

Hence t = 14.9 years.

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y′′ −y = 0, x0 = 0 Seek power series solutions of the given differential equation about the given point x 0; find the recurrence
sukhopar [10]

Let

\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots

Differentiating twice gives

\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots

\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0

\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0

Then the coefficients in the power series solution are governed by the recurrence relation,

\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

k=0 \implies n=0 \implies a_0 = a_0

k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}

k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}

k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}

It should be easy enough to see that

a_{n=2k} = \dfrac{a_0}{(2k)!}

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

k = 0 \implies n=1 \implies a_1 = a_1

k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}

k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}

k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}

so that

a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}

So, the overall series solution is

\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)

\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}

4 0
2 years ago
I need help answer 6 through 7 I can't figure them out
seropon [69]
6. the answer is 4. because u find the diameter by dividing by 2. 
7. answer = 8 , the radius is 4 . so u need to multiply 2 times 4. 2 times 4 =8.
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3 years ago
Jodie wants to raise money for a school trip by selling raffle tickets at a basketball game. She sells each ticket for 50 cents,
wel

Answer:

250 dollars

Step-by-step explanation:

t = tickets

t = 200

Two and a half rolls tickets = (200 x 2) + 200/2) = 400 + 100 = 500

500 tickets x 50 cents = 25000 cents

convert cents to dollars (move decimole point over left 2 units)

25000 = 250 dollars

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3 years ago
What is the value of the expression, written in standard form? (6.6x10^-2)/(3.3x10^-4)
Eduardwww [97]
0.066/0.00033
The answer is 200.
4 0
3 years ago
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Steph makes 90 % 90%90, percent of the free throws she attempts. She is going to shoot 3 33 free throws. Assume that the results
zmey [24]

Using the binomial distribution, it is found that there is a 0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

For each free throw, there are only two possible outcomes, either he makes it, or he misses it. The results of free throws are independent from each other, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • He makes 90% of the free throws, hence p = 0.9.
  • He is going to shoot 3 free throws, hence n = 3.

The probability that he makes exactly 1 is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.9)^{1}.(0.1)^{2} = 0.027

0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

3 0
2 years ago
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