Answer:
The numbers are -14,-13 and -12
Step-by-step explanation:
<u><em>The correct question is </em></u>
Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?
Let
x ----> the first consecutive integer
x+1 ---> the second consecutive integer
x+2 ---> the third consecutive integer
we have that
solve for x
apply distributive property
Combine like terms
subtract 8 both sides
Divide by 6 both sides
so
therefore
The numbers are -14,-13 and -12
Answer:
225 quarters are easy to loose and who will accept that many quarters
Step-by-step explanation:
Answer:
step by step Explanation:
Since this is a right triangle,
We can find the length b by using the Pythagoras theorem
a2+b2=c2
Plugin the values
→22+b2=62
→4+b2=36
→b2=32
Take the square root of both sides
→√b2=√32
→b=√16⋅2
⇒b=4√2
Answer:
? = (x + 7)
Step-by-step explanation:
2x^2 + 15x + 7 = (2x + 1) (?)
1. First you need to figure out what multiplied by 2x will give you 2x^2, which is x.
2. Then you need to find what would give you 15x. In this case because you have the 1 in (2x + 1), you already know that there is going to be an extra x. So, what times 2x gives you 14x? It's 7.
3. Lastly you need to make sure that 1 multiplied with 7 is equal to 7 and combine like terms.
4. Check: (2x + 1) (x + 7) =
2x^2 + 14x + 1x + 7 =
2x^2 + 15x + 7
