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Tema [17]
3 years ago
8

Solve the quadratic equation by completing the square. x2 + 4x - 3 = 0

Mathematics
1 answer:
alukav5142 [94]3 years ago
6 0
First move the constant to the other side of the equation by adding 3 to both sides...

x^2+4x=3

Now halve the linear coefficient, 4/2=2, square it, 2^2=4, and add that value to both sides...

x^2+4x+4=7, now the left side is a perfect square of the form...

(x+2)^2=7, now take the square root of both sides...

x+2=±√7,  subtract 2 from both sides...

x=-2±√7

So x=-2-√7 and -2+√7
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The area of a circle is 43.25cm2.<br> Find the length of the radius rounded to 2 DP.
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Answer:

3.71 cm

Step-by-step explanation:

Hi there!

Area of a circle equation: A=\pi r^2 where r is the radius

Plug in the area 43.25 cm²

43.25=\pi r^2

Divide both sides by π to isolate r²

\frac{43.25}{\pi} =\frac{\pi r^2}{\pi} \\\frac{43.25}{\pi}=r^2

Take the square root of both sides to isolate r

\sqrt{\frac{43.25}{\pi}} =r\\3.71=r

Therefore, the length of the radius rounded to 2 decimal points is 3.71 cm.

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ElenaW [278]

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

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Step-by-step explanation:

Brittany paints the room in x hours, completing 1/x of the room per hour.

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6-√51 is an extraneous solution.

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