Answer:
I think it is (x^2+9) x (x-1) x (x+1)
Step-by-step explanation:
(not sure if right but had a go)
1) Slope tell about the steepness of the line.
To find slope we look at the rise and run between 2 points.
attached the graph of line with slope
slope = 
= 
So slope = 2
2) we have x and y intercepts
x intercept is the point where the line crosses x axis
x intercept at x= 3
y intercept is the point where the line crosses y axis
y intercept at y= 6
3) Linear equation is y= 3x+2
function is f(x) = 3x+2
We can graph it using slope and y intercept
In f(x)= 3x + 2 , slope =3 and y intercept = 2
slope = 3, rise = 3 and run =1
The graph of f(x)= 3x+2 is attached below.
The formula of a slope:

We have the points A(-7, a) and B(c, d).
Substitute:

Exception: c ≠ -7.
Answer: The value necessary from the set to make the equation true was 11.
Step-by-step explanation:
Process of elimination:
1. 2([10]-5)
= 2(5)
= 10, not 12.
2. 2([11]-5)
= 2(6)
= 12; the answer we need.
We substituted x for 11, and then the equation worked; so therefore the value we needed from the set was 11.