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MatroZZZ [7]
3 years ago
14

Please help me!!! I don't understand how to solve it(((

Mathematics
1 answer:
olganol [36]3 years ago
4 0
\sqrt{( \sqrt{7-2 \sqrt{10} }+ \sqrt{2} )*2 \sqrt{5}  }=  \\ = \sqrt{( \sqrt{2-2 \sqrt{2*5}+5 }+ \sqrt{2} )*2 \sqrt{5}  }= \\  \sqrt{( \sqrt{( \sqrt{2}- \sqrt{5})^{2}    }+ \sqrt{2} )*2 \sqrt{5}  }= \\  \sqrt{(  \sqrt{5}-  \sqrt{2} + \sqrt{2} )*2 \sqrt{5}  }= \\ \sqrt{  \sqrt{5} *2 \sqrt{5}  }=   \\  \sqrt{2*5} = \sqrt{10}
HAVE A NICE DAY!! ^^
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Starting with the formula for the difference of cubes, which pair of steps can be used to show that the expressions are
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I need this answer following the order of operation. Please help!
natita [175]

Answer:

The answer to the question provided is 1.

8 0
3 years ago
Christian invested $2,300 in an account paying an interest rate of 5.5% compounded monthly. Assuming no deposits or withdrawals
Blizzard [7]

Answer: A = $4,830.00

(I = A - P = $2,530.00)

Step-by-step explanation:

Equation:

A = P(1 + rt)

Calculation:

First, converting R percent to r a decimal

r = R/100 = 5.5%/100 = 0.055 per year.

Solving our equation:

A = 2300(1 + (0.055 × 20)) = 4830

A = $4,830.00

The total amount accrued, principal plus interest, from simple interest on a principal of $2,300.00 at a rate of 5.5% per year for 20 years is $4,830.00.

4 0
3 years ago
What is the outlier in the following data set:<br> 15,11,10,8,9,1,8,7,5,4,2,3, and 37?
NeTakaya

Step-by-step explanation:

The steps to find an outlier:

1. Put the data in numerical order.

2. Find the median.

3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.

The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.

4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.

5. Multiply...1.5 * IQR

6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.

7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.

For your data....the median, Q2 is

(43+38)/2 = 40.5.

Q1 = (30+26)/2 = 28.

Q3 = (54+52)/2 = 53

The IQR is 53 - 28 = 25

1.5 * IQR = 37.5

Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.

Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.

My conclusion is that there are no outliers in this data.

I hope this helps!

4 0
3 years ago
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