Answer:
(A)


(B)

(C)

(D)
The high school's enrollment in 2017 is 2500
Step-by-step explanation:
Let's assume time starts since 2009
so, In 2009 , t=0
P=900
In 2012,
t=2012-2009=3
P=1500
(A)
So, we have points as
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
(B)
we can use slope formula

we can plug values


we know that
slope is rate of change of P with respect to time
so, slope means increase in population is 200 per year
(C)
we can use point slope form of line





(D)
In 2017 ,
t=2017-2009=8
we can plug t=8
and we get


The high school's enrollment in 2017 is 2500
These are linear equations, so there is x and y. On number one the first thing they plotted was (3,8) so in a function table the 3 would be on the left side and the 8 would be on the right side. I’ll leave you with the rule of the first one, if the rule is times 2 plus to the how would you put it in a function table.
The first thing that you would put into the function table on the first question would be as I said earlier 3 and then 8. The rule is the rate. Using a function table will be very helpful (That’s why I keep mentioning one). Let me know if this helps.
Answer:
(x, y ) --> (x - 1, y - 4)
Step-by-step explanation:
Since you subtract 1 from the x coordinate and subtract 4 from the y coordinate, the rule would be:
(x, y ) --> (x - 1, y - 4)
2x + 5y = 34
x+2y = 14
Multiply the second equation by two to create like terms for one variable.
2(x+2y = 14)
2x + 4y = 28
2x + 5y = 34
2x + 4y = 28 -- Subtract.
y = 34.28 = 6
Solve for x
x + 2(6) = 14
x + 12 = 14
x = 2
Check:
2 + 2(6) = 14
2 + 12 = 14
14 = 14
Answer:
X = 2
Y = 6
Answer:
Perpendicular lines are lines that intersect at a right (90 degrees) angle.so no form of perpendicular for angles except 90° angles
Step-by-step explanation:
Two lines are perpendicular if and only if they form a right angle. Perpendicular lines (or segments) actually form four right angles, even if only one of the right angles is marked with a box.