All categories

3 years ago

Please help will mark brainly

Mathematics

2 answers:

Eddi Din [679]3 years ago

7 0

Answer:

Step-by-step explanation:

Hanna has 3bags of potato

Let the 3bags have x kg

Each of the bag is 2⅔kg

2⅔kg is a mixed fraction, so let convert to improper fraction

Then, 2⅔kg=8/3 kg

Given that

1bag=8/3 kg

3bags= x kg

Then cross multiply

1×x=8/3 × 3

x=8kg

So the 3bags Hanna has is 8kg.

The correct answer is B

Slav-nsk [51]3 years ago

4 0

the answer is B because

2 2/3 = 8/3

8/3 x 3 = 24/3

24/3 = 8

I hope this helps

You might be interested in

If f(x) = + 8, what is f(x) when x = 10?<br> Help

Reptile [31]

Step-by-step explanation:

f(x) = + 8

x = 10?

f(10)= +8

no change

5 0

3 years ago

Read 2 more answers

6000 is deposited into a fund at the annual rate of 9.5%. Find the time required for the investment to double if the interest is

Anna [14]

Answer: 7.58 years

Step-by-step explanation:

When it comes to finding out how long it will take for an investment to double, one can use the Rule of 72.

The Rule of 72 estimates the amount of time it will take to double an investment when you divide 72 by the interest rate:

= 72 / r

= 72 / 9.5

= 7.58 years

3 0

2 years ago

Find the TWO integers whos product is -12 and whose sum is 1<br>

julsineya [31]

Answer:

$\rm Numbers = 4 \ and \ -3.$

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

$\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}$

Hence the numbers are 4 and -3

5 0

3 years ago

Given that CD¯¯¯¯¯¯¯¯ is a perpendicular bisector of AB¯¯¯¯¯¯¯¯, where D is on AB¯¯¯¯¯¯¯¯, how can you use the Pythagorean Theor

Liula [17]

Answer:

$(AD)^2 + (CD)^2 = (CA)^2$ and $(CD)^2 + (BD)^2 = (CB)^2$

Step-by-step explanation:

Given

Bisector: CD

of Line AB

Required

Apply Pythagoras Theorem

From the question, CD bisects AB and it bisects it at D.

The relationship between AB and CD is given by the attachment

Considering ACD

From the attachment, we have that:

$Hypothenuse = CA$

$Opposite = CD$

$Adjacent = AD$

By Pythagoras Theorem, we have

$(AD)^2 + (CD)^2 = (CA)^2$

Considering CBD

From the attachment, we have that:

$Hypothenuse = CB$

$Opposite = CD$

$Adjacent = BD$

By Pythagoras Theorem, we have:

$(CD)^2 + (BD)^2 = (CB)^2$

4 0

3 years ago

Read 2 more answers

Is anybody else here to help me ??

Akimi4 [234]

Answer:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

Step-by-step explanation:

I'm going to use $x$ instead of $\theta$ because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

$\cot(x)+\cot(\frac{\pi}{2}-x)$

I'm going to use a cofunction identity for the 2nd term.

This is the identity: $\tan(x)=\cot(\frac{\pi}{2}-x)$ I'm going to use there.

$\cot(x)+\tan(x)$

I'm going to rewrite this in terms of $\sin(x)$ and $\cos(x)$ because I prefer to work in those terms. My objective here is to some how write this sum as a product.