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3 years ago

Verify the identity. cos quanity x plus pi divided by two = -sin x

Mathematics

1 answer:

7nadin3 [17]3 years ago

4 0

Answer:

see below

Step-by-step explanation:

cos ( x+pi/2) = -sinx

We know that

cos(A + B) = cos A cos B - sin A sin B

Let x = A and pi/2 = B

cos x cos pi/2 - sin x sin pi/2 = -sin x

We know cos pi/2 = 0 and sin pi/2 = 1

cos x * 0 - sin x *1 = -sin x

- sin x = - sin x

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That is the equation in slope intercept form.

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3 years ago

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Type the correct answer in the box. Use numerals instead of words.

Mandarinka [93]

Answer:

Step-by-step explanation:

We are here given a modulus expression and we need to find out the value when m = -5 and n = 3 .

Modulus :- It always gives positive value . For example ,

$\rm\implies |-a| = a$

$\rm\implies |a| = a$

The given modulus expression is :-

$\rm\implies |m^2+ n^2|$

As the number inside the modulus operator are already squared therefore they will always give positive value for real numbers . Here we can omit the modulus .

$\rm\implies m^2 + n^2$

Plug in the given values ,

$\rm\implies (-5)^2 + 3^2$

Solve 5² and 3² and add them ,

$\rm\implies 25 + 9$

On adding ,

$\rm\implies 34$

Therefore ,

$\rm\implies \boxed{\blue{\rm |m^2+n^2| = 34 }}$

Hence the required answer is 34 .

8 0

2 years ago

Carisoprodol, a generic muscle relaxer, claims to have, on average, at least 120 milligrams of active ingredient. An independent

katovenus [111]

Answer:

The approximate p-value for the suitable test

0.05

|t| = |-1.5806| = 1.5806

t = 1.5806 < 2.009 at 0.05 level of significance

Carisoprodol, a generic muscle relaxer, claims to have, on average, is equal to 120 milligrams of active ingredient.

Step-by-step explanation:

Step(i):-

Given mean of the Population 'μ' = 120 milligrams

Given random sample size 'n' = 50

Given mean of the sample x⁻ = 116.2 milligrams

Standard deviation of the sample 'S' = 17 milligrams

Null hypothesis : 'μ' = 120

Alternative hypothesis : 'μ' < 120

Step(ii):-

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{116.2 - 120}{\frac{17}{\sqrt{50} } } = \frac{-3.8}{2.404} = -1.5806$

Degrees of freedom

ν = n-1 = 50 -1 =49

t₀.₀₅ = 2.009

|t| = |-1.5806| = 1.5806

t = 1.5806 < 2.009 at 0.05 level of significance

Null hypothesis is accepted

Carisoprodol, a generic muscle relaxer, claims to have, on average, is equal to 120 milligrams of active ingredient.

P- value:-

The test statistic |t| = 1.5806 at 49 degrees of freedom

The test statistic value is lies between 0.05 to 0.1

0.05

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2 years ago