Answer:
Step-by-step explanation:
product of slopes of perpendicular lines=-1
(t-5)/(3+4)×(2-3)/(-4-1)=-1
(t-5)/7×(-1/-5)=-1
(t-5)/35=-1
t-5=-1×35=-35
t=-35+5
t=-30
2.
slopes of parallel lines are equal.
(-2+3)/(t-4)=(-1-4)/(4+2)
1/(t-4)=-5/6
t-4=-6/5
t=4-6/5=(20-6)/5=14/5
3.
x>0,y<0
so P lies in4th quadrant.
except cos and sec all are negative.
so only cos and sec are positive.
Answer: Option b.
Step-by-step explanation:
1. You can rewrite it as following:

This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 2, no matter the value of x.


This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 1, no matter the value of x.

2. Then:

3. The answer 2.
Answer:
Step-by-step explanation:
Answer: 
<u>Step-by-step explanation:</u>
Think of the products row by row:
11 12 13 14 15 16 - 0 products greater than 6
21 22 23 24 25 26 - 3 products greater than 6
31 32 33 34 35 36 - 4 products greater than 6
41 42 43 44 45 46 - 5 products greater than 6
51 52 53 54 55 56 - 5 products greater than 6
61 62 63 64 65 66 - 5 products greater than 6
