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sdas [7]
3 years ago
13

Please show work if possible, it would be greatly appreciated. Thank you SOOOOO much!!!

Mathematics
1 answer:
o-na [289]3 years ago
8 0
When you solve this equation, you can plug in 2x + 10 for y, so you would have 2x + 10 = 2x +4. When you solve for x, you notice that you end up getting 10 = 4, which is impossible!

There are NO solutions for this, because 10 will never equal 4.

The slope of the first line is 2.

The slop of the second line is also 2.

The lines ARE parallel- they have the same slope!

They do not have the same y-intercept, one of them crosses at y=4, and the other crosses at y=10.

Since the lines are parallel, they will never cross, which is why there are no solutions for this equation.

Hope this helps! :)
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When a family with two adults and three children bough the tickets for an amusement park, the young paid a total of $56.50. the
vitfil [10]
2a+3c=56, a+4c=49.50

     2a+3c=56.00
 -2(a+4c=49.50)
_______________
2z+3c=56
-2a-8c=99
____________
0+-5c=-43
     -5c=-43
      c= -43/-5
     child ticket=8.60
now take c and plug the answer into the first equation: 2a+3c=56, 2z+3(8.60)=56,  2z+25.80=56,  2a=56-25.80,  2a= 30.20, a=30.20/2, adult tickets =15.10
4 0
3 years ago
Comeplete the equivalent equation of -7x-60=x(2)+10x
MariettaO [177]

Answer:

3 \frac{3}{ 19}

8 0
3 years ago
What decimal is equivalent to 5.8
Mkey [24]

Answer: 5.8% = 0.058 in decimal form.

Step-by-step explanation:

6 0
4 years ago
The number of errors in a textbook follow a poisson distribution with a mean of 0.01 errors per page. what is the probability th
neonofarm [45]
Mean number of errors in each page = 0.01
Mean number of errors in 100 pages = 0.01*100=1

It is possible to use the cumulative distribution function (CMF), but the math is a little more complex, involving the gamma-function.  Tables and software are available for that purpose.

Thus it is easier to evaluate with a calculator for the individual cases of k=0,1,2 and 3.

The Poisson distribution has a PMF (probability mass function) 
P(k):=\frac{\lambda^ke^{-\lambda}}{k!}
with λ = 1
=>
P(0):=\frac{1^0e^{-1}}{0!}=0.3678794
P(1):=\frac{1^1e^{-1}}{1!}=0.3678794
P(2):=\frac{1^2e^{-1}}{2!}=0.1839397
P(3):=\frac{1^3e^{-1}}{3!}=0.0613132
=>
P(k
or
P(k<=3)=0.9810 (to four decimal places)
3 0
3 years ago
I'LL GIVE 25 POINTS!!!
pickupchik [31]

Answer:

i cant see the photo its messy or is it just me

Step-by-step explanation:

4 0
3 years ago
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