2a+3c=56, a+4c=49.50
2a+3c=56.00
-2(a+4c=49.50)
_______________
2z+3c=56
-2a-8c=99
____________
0+-5c=-43
-5c=-43
c= -43/-5
child ticket=8.60
now take c and plug the answer into the first equation: 2a+3c=56, 2z+3(8.60)=56, 2z+25.80=56, 2a=56-25.80, 2a= 30.20, a=30.20/2, adult tickets =15.10
Answer: 5.8% = 0.058 in decimal form.
Step-by-step explanation:
Mean number of errors in each page = 0.01
Mean number of errors in 100 pages = 0.01*100=1
It is possible to use the cumulative distribution function (CMF), but the math is a little more complex, involving the gamma-function. Tables and software are available for that purpose.
Thus it is easier to evaluate with a calculator for the individual cases of k=0,1,2 and 3.
The Poisson distribution has a PMF (probability mass function)


with λ = 1
=>




=>

or
P(k<=3)=
0.9810 (to four decimal places)
Answer:
i cant see the photo its messy or is it just me
Step-by-step explanation: