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sdas [7]
3 years ago
13

Please show work if possible, it would be greatly appreciated. Thank you SOOOOO much!!!

Mathematics
1 answer:
o-na [289]3 years ago
8 0
When you solve this equation, you can plug in 2x + 10 for y, so you would have 2x + 10 = 2x +4. When you solve for x, you notice that you end up getting 10 = 4, which is impossible!

There are NO solutions for this, because 10 will never equal 4.

The slope of the first line is 2.

The slop of the second line is also 2.

The lines ARE parallel- they have the same slope!

They do not have the same y-intercept, one of them crosses at y=4, and the other crosses at y=10.

Since the lines are parallel, they will never cross, which is why there are no solutions for this equation.

Hope this helps! :)
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the practice of analyzing and describing a complex phenomenon in terms of phenomena that are held to represent a simpler or more fundamental level, especially when this is said to provide a sufficient explanation.

Step-by-step explanation:

from dictionary . com or smth

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Let's make another angle y

Where y= 51° (corresponding angles )

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Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima
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0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416

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