You can resolve all of them.
so the first one would be 3q+2p
that second 2p+3q
the third 2p+2q+q which equals 2p+3q
they all end up as the same thing so both are equivalent
Since the stadium is 6 mi from the practice field which is itself 1 mi from the house, it can either be (1+6)=7 mi North or (1-6)=-5 -> 5 mi South depending on the North/South direction.
the answer is thus A
The lengths of the sides are 7, 23 and 24.
In order to find this, we need to add all of the side lengths together and set equa to 54. This will allow us to solve for n.
n + 3n + 2 + 4n - 4 = 52
8n - 2 = 52
8n = 54
n = 7
This gives us the length of the first side. To solve for the others, plug 7 into the equations.
3n + 2
3(7) + 2
21 + 2
23
Then the next one.
4n - 4
4(7) - 4
28 - 4
24
When the lines are parallel, the slope have to be the same for both and we know that the slope of line B is 5/2, so the answer would be D) 5/2
