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ANEK [815]
3 years ago
11

Factoring polynomial expressions(quadratic) x^2-6x+5

Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0

Answer:

x = 5 and x = 1 are the factors

Step-by-step explanation:

<h2>step 1) </h2>

identify the a, b, and c values (a=1 b= -6 c=5)

<h2>step 2) </h2>

plug them into the quadratic formula

x = -(-6) ± √(-6)² - 4(1)(5) / 2(1)

<h2>step 3) </h2>

multiply -1 by -6 to get 6

x = 6 ± √(-6)² - 4(1)(5) / 2(1)

<h2>step 4)</h2>

multiply -6 by -6 to get 36

x = 6 ± √36 - 4(1)(5) / 2(1)

<h2>step 5)</h2>

multiply 4 by 1 to get 4

x = 6 ± √36 - 4(5) / 2(1)

<h2>step 6) </h2>

multiply 4 by 5 to get 20

x = 6 ± √36 - 20 / 2(1)

<h2>step 7)</h2>

subtract 36 by 20 to get 16

x = 6 ± √16 / 2(1)

<h2>step 8) </h2>

take the square root of 16 to get 4

x = 6 ± 4 / 2(1)

<h2>step 9)</h2>

multiply 2 by 1 to get 2

x = 6 ± 4 / 2

<h2>step 10) </h2>

add 6 by 4 to get 10

x = 10 / 2

<h2>step 11) </h2>

divide 10 by 2 to get 5 (now you know the first factor is x=5)

x = 5

<h2>step 12)</h2>

subtract 6 by 4 to get 2

x = 2 / 2

<h2>step 13)</h2>

divide 2 by 2 to get 1 (now you have found the final factor x=1)

<h2>step 14)</h2>

you know know that the factors of x²- 6x + 5 are<em><u> x = 5 and x = 1</u></em>

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