Question

Complete the equation of the line through ( -6 , 5 ) and ( -3 , -3 )

Answer 1

Answer:

$y = (\frac{8}{-3})(x) - 16$

Step-by-step explanation:

The given points are (-6,5) and (-3,-3)

The equation of the line is of the form,

$(y-y1) = m(x-x1)$ , m is the slope of line and (x1,y1) is one of the end points.

The slope m of the line is calculated as,

$\frac{(y2)-(y1)}{(x2)-(x1)} = \frac{(5)-(-3)}{(-6)-(-3)} = \frac{8}{-3}$

Thus the line equation is,

$(y-5) = (\frac{8}{-3})(x-(-6))$

$y = (\frac{8}{-3})(x-(-6)) + 5$

$y = (\frac{8}{-3})(x) - 16$