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Digiron [165]
4 years ago
15

Seattle, wa and san francisco, ca lie on the same longitudinal line. san francisco is at 38° latitude and seattle is at 47° lati

tude. if the earth is a sphere of radius 4000 miles, use arc length to find the distance between the cities. [use π = 3.14, and round to the nearest mile.]

Mathematics
1 answer:
Dennis_Churaev [7]4 years ago
3 0

Step 1.

Calculate measure of angle α:

47^o-38^o=9^o

Step 2.

Calculate what fraction of the angle 360° ​​is the angle α:

\dfrac{9^o}{360^o}=\dfrac{1}{40}

Step 3.

Calculate the circumference of the Earth (circle):

C=2\pi r\to C=2\pi\cdot4000=8000\pi\ mi

Step 4.

The length of arc is equal 1/40 of the circumference:

\dfrac{1}{40}C=\dfrac{1}{40}\cdot8000\pi=200\pi\ mi

\pi\approx3.14\to\dfrac{1}{40}C\approx200\cdot3.14=628\ mi


<h3>Answer: A) 628 miles</h3>

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tatyana61 [14]

Answer:

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23z = 18 \\ z =  \frac{18}{23}  \\ z = 0.782

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

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7 0
3 years ago
Read 2 more answers
Answer soon please! Question and answers are in the photograph attached.
-BARSIC- [3]

Answer:

Δ MLP  ~  Δ HKG

By S-A-S similarity Postulate.

Step-by-step explanation:

Given:

In Δ MLP

MP = 20 ,

LP = 15

∠ P = 42°

In Δ HKG

HG = 16 ,

KG = 12

∠G = 42°

To Prove:

Δ MLP ~Δ HKG

Proof:

In Δ MLP and Δ HKG

\dfrac{MP}{HG}= \dfrac{20}{16}=\dfrac{5}{4} ..........( 1 )

\dfrac{LP}{KG}= \dfrac{15}{12}=\dfrac{5}{4}  ..............( 2 )

∴ \dfrac{MP}{HG}=\dfrac{LP}{KG} ...From 1 and 2

       ∠P ≅ ∠ G = 42°          ...............Given

∴ Δ MLP ~Δ HKG ......{ By S-A-S similarity test}............Proved

4 0
3 years ago
How do I do this?<br> Thank you!
saveliy_v [14]
Can you post a more clear picture
6 0
4 years ago
Read 2 more answers
?
alexgriva [62]

Answer:

16 the answer is 1, 4, 5, 6, yeah good answer

5 0
2 years ago
Easy math!! Please help me I'm on a time crunch!!! &gt;﹏&lt;<br><br>^^
sukhopar [10]

Answer: the 3rd one.

7 0
3 years ago
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