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Rina8888 [55]
3 years ago
10

Find the discriminant: * 7x2 – 5 = 2x + 9x2

Mathematics
1 answer:
Fed [463]3 years ago
6 0

Answer:

-36

Step-by-step explanation:

You have to rearrange the quadratic into an equation where one side is zero.

This example works by subtracting 7x^2 from both sides leaving

-5 = 9x^2 - 7x^2 + 2x

-5 = 2x^2 + 2x

Now add 5 to both sides

-5 + 5 = 2x^2 + 2x + 5

0 = 2x^2 + 2x + 5

Now the equation you gave is in the form of a quadratic. The discriminate is found from

a = 2

b = 2

c = 5

b^2 - 4ac is the discriminate

2^2 - 4(2)(5)

4 - 40

Discrimate = 4 - 40 = - 36

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yKpoI14uk [10]

Answer:

\displaystyle  a_{1}    = 108

Step-by-step explanation:

we are given

the sum,common difference and nth term of a geometric sequence

we want to figure out the first term

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\displaystyle S_{ \text{n}} =  \frac{ a_{1}(1 -  {r}^{n} )}{1 - r}

we are given that

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thus substitute:

\displaystyle 189=  \frac{ a_{1}(1 -  {( \frac{1}{2} )}^{3} )}{1 -  \frac{1}{2} }

to figure out a_1 we need to figure out the equation

simplify denominator:

\displaystyle  \frac{ a_{1}(1 -  {( \frac{1}{2} )}^{3} )}{ \dfrac{1}{2}  }  = 189

simplify square:

\displaystyle  \frac{ a_{1}(1 -  {( \frac{1}{8} )}^{} )}{ \dfrac{1}{2}  }  = 189

simplify substraction:

\displaystyle  \frac{ a_{1} (\frac{7}{8} )}{ \frac{1}{2}  }  = 189

simplify complex fraction:

\displaystyle   a_{1} (\frac{7}{8} ) \div { \frac{1}{2}  }  = 189

calculate reciprocal:

\displaystyle   a_{1} \frac{7}{8}   \times 2  = 189

reduce fraction:

\displaystyle   a_{1} \frac{7}{4}   \  = 189

multiply both sides by 4/7:

\displaystyle   a_{1} \frac{7}{4}  \times  \frac{4}{7}   \  = 189 \times  \frac{4}{7}

reduce fraction:

\displaystyle   a_{1}     = 27\times  4

simplify multiplication:

\displaystyle  a_{1}    = 108

hence,

\displaystyle  a_{1}    = 108

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yKpoI14uk [10]
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Answer:

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find the cross sectional area which is the triangle

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